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Mice21 [21]
1 year ago
6

An electron with an initial speed of 340,000 m/s

Physics
1 answer:
loris [4]1 year ago
6 0

Answer:

0,33  Volt

Explanation:

v = 340 000 m/s - Initial electron speed

m = 9.1·10⁻³¹ kg - Mass of an electron

W = m·v² / 2 - Initial kinetic energy of an electron

W = 9.1·10⁻³¹·(340 000)² /2 ≈ 5.26 · 10⁻²⁰ J       (1)

Q = 1.6·10⁻¹⁹  C  - Electron charge modulus

The work of the electric field:

A = Q·V   (2)  

Equate (2) and (1):

Q·V = W

V - Electric field potential difference

V = W / Q = 5.26 · 10⁻²⁰ / 1.6·10⁻¹⁹ ≈ 0,33  Volt

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