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natima [27]
3 years ago
8

Solve this questions please ​

Physics
1 answer:
Rudik [331]3 years ago
4 0

Answer:

10.37×10³j

Explanation:

hope this helps you !!!

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How long will it take to travel 200.000 m [N] traveling 10 m/s [N]?
gtnhenbr [62]

Answer: here are 1,000m in a km, so 200km is 200,000m

200,000m/10m/s = 20,000s

Explanation:

8 0
2 years ago
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Ian and Dane are twins. Ian loves art and music and work after school. Dane loves sports and would do anything to avoid having a
Brilliant_brown [7]

Answer:

Explanation:

Pliability

5 0
3 years ago
Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant
Nimfa-mama [501]

Answer:

25 m/s

Explanation:

Given that:

Initial speed, u = 4 m/s

Final velocity, V = 11 m/s

Time, t = 8 seconds

t2, = 16 seconds

Acceleration, a= (change in velocity) / time interval

a = (11 - 4) / 8

a = 7 / 8 = 0.875m/s²

Final velocity, v2 ;

Acceleration * t2

0.875 * 16 = 14

V2 = 14 m/s

Final speed : v + v2 = (11 + 14)m/s = 25m/s

3 0
3 years ago
While exploring a castle, Exena the Exterminator is spotted by a dragon who chases her down a hallway. Exena runs into a room an
Bogdan [553]

Answer:

the time needed for her to close the door is 1.36 s.

Explanation:

given information:

Force, F = 220 N

width, r = 1.40 m

weight, W = 790 N

height, h = 3.00 m

angle, θ = 90° = π/2

to find the times needed to close the door we can use the following equation

θ = ω₀t + 1/2 αt²

where

θ = angle

ω = angular velocity

α = angular acceleration

t = time

in this case, the angular velocity is zero. thus,

θ = 1/2 αt²

now, we can find the angular speed by using the torque formula

τ = I α

where

τ = torque

I = Inertia

we know that

τ = F r

and

I = 1/3 mr²

so,

τ = I α

F r = 1/3 mr² α

α = 3 F/mr

  = 3 F/(w/g)r

  = 3 (220)/(790/9.8) 1.4

  = 5.85 rad/s²

θ = 1/2 αt²

π/2 = 1/2 5.85 t²

t = 1.36 s

5 0
3 years ago
A certain piece of metal (density 9.45 grams per cubic centimeter) has the shape of a hockey puck with a diameter of 13 cm and a
atroni [7]

Answer:

0.0195 m

Explanation:

\rho _{p} = density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³

d_{p} = diameter of hockey puck = 13 cm = 0.13 m

h_{p} = height of hockey puck = 2.8 cm = 0.028 m

\rho _{m} = density of mercury = 13.6 gcm⁻³ = 13600 kgm³

d = depth of puck below surface of mercury

According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck

Weight of mercury displaced = Weight of puck

\rho _{m} (0.25)(\pi d_{p}^{2} d ) g = \rho _{p} (0.25)(\pi d_{p}^{2} h_{p} ) g\\\rho _{m} ( d ) = \rho _{p} ( h_{p} )\\(13600) d = (9450) (0.028)\\d = 0.0195 m

7 0
3 years ago
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