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marusya05 [52]
1 year ago
11

predict the sign on the thermodynamic quantities listed below based on the scene representing a physical change in a piston-cyli

nder assembly.
Chemistry
1 answer:
brilliants [131]1 year ago
4 0

Based on a scene showing a physical change in a piston-cylinder assembly, the thermodynamic numbers indicated below are 760 torr 760.

<h3>What elements make up the first rule of thermodynamics?</h3>

The first law of thermodynamics states that the following equation describes how the change in internal energy relates to the heat exchanged by the system and the work performed on or by the system: U = Q + W, where Q represents the heat energy that the system exchanged.

<h3>What are the thermodynamic quantities' two components?</h3>

Extensive and intensive thermodynamic quantities are traditionally separated into these two categories. While intensive quantities are independent of system size, extensive quantities grow linearly with system size.

To know more about thermodynamic visit:-

brainly.com/question/1368306

#SPJ4

You might be interested in
Consider the following reaction at equilibrium. What effect will decreasing the temperature have on the system? DH=+890kJCO2(g)+
AlladinOne [14]

Answer:

Option B. The reaction will shift to the left in the direction of the reactants.

Explanation:

The equation for the reaction is given below:

CO₂ + 2H₂O <=> CH₄ + O₂

Enthalpy change (ΔH) = +890 KJ

The reaction illustrated by the equation is endothermic reaction since the enthalpy change (ΔH) is positive.

Increasing the temperature of an endothermic reaction will shift the equilibrium position to the right and decrease the temperature will shift the equilibrium position to the left.

Therefore, decreasing the temperature of the system illustrated by the equation above, will shift the reaction to the left in the direction of the reactants.

Thus, option B gives the right answer to the question.

3 0
3 years ago
Ethanol is a common laboratory solvent and has a density of 0.789 g/ml. What is the mass, in pounds, of 39.0 gallons of ethanol?
USPshnik [31]

Mass = 39.0 gal × (3.785 L/1 gal) × (1000 mL/1 L) × (0.789 g/1 mL) × (1 lb/453.6 g) = 257 lb

3 0
3 years ago
To what temperature in kelvin will a 2.3 L balloon have to be heated to expand to a volume of 400 L Assume the initial temperatu
olchik [2.2K]

Answer:

T₂ = 51826.1 K

Explanation:

Given data:

Initial Volume = 2.3 L

Final volume = 400 L

Initial temperature = 25 °C (25+ 273 = 298 K)

Final temperature = ?

Solution:

V₁/T₁ = V₂/T₂

T₂ = V₂ T₁/V₁

T₂ =  400 L . 298 K / 2.3 L

T₂ = 119200 K. L / 2.3 L

T₂ = 51826.1 K

7 0
3 years ago
Susan did an experiment in which she heated cog of CaCO3 to obtain 5.6g of Ca and 4.4g of Cow. is the law of conservation of mas
patriot [66]

Answer:

no

Explanation:

5 0
2 years ago
what is the percent yield of titanium (II) oxide if 20.0 grams of titanium (II) sulfide is reacted with water? The actual yield
earnstyle [38]

Answer : The percent yield of titanium (II) oxide is, 142.5 % and the impurities could have caused the percent yield to be so high.

Explanation : Given,

Mass of titanium(II) sulfide = 20.0 g

Molar mass of titanium(II) sulfide = 79.9 g/mole

Molar mass of titanium(II) oxide = 63.9 g/mole

First we have to calculate the moles of titanium(II) sulfide.

\text{ Moles of titanium(II) sulfide}=\frac{\text{ Mass of titanium(II) sulfide}}{\text{ Molar mass of titanium(II) sulfide}}=\frac{20.0g}{79.9g/mole}=0.2503moles

Now we have to calculate the moles of titanium(II) oxide.

The balanced chemical reaction is,

TiS+H_2O\rightarrow TiO+H_2S

From the reaction, we conclude that

As, 1 mole of titanium(II) sulfide react to give 1 mole of titanium(II) oxide

So, 0.2503 mole of titanium(II) sulfide react to give 0.2503 mole of titanium(II) oxide

Now we have to calculate the mass of titanium(II) oxide.

\text{ Mass of titanium(II) oxide}=\text{ Moles of titanium(II) oxide}\times \text{ Molar mass of titanium(II) oxide}

\text{ Mass of titanium(II) oxide}=(0.2503moles)\times (63.9g/mole)=15.99g

To calculate the percentage yield of titanium (II) oxide, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of titanium (II) oxide = 22.8 g

Theoretical yield of titanium (II) oxide = 15.99 g

Putting values in above equation, we get:

\%\text{ yield of titanium (II) oxide}=\frac{22.8g}{15.99g}\times 100\\\\\% \text{yield of titanium (II) oxide}=142.5\%

Hence, the percent yield of titanium (II) oxide is, 142.5 %

If the percent yields is greater than 100% that means the product of the reaction contains impurities which cause its mass to be greater than it actually.

5 0
3 years ago
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