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Free_Kalibri [48]

4 years ago

10

20 pts ‼️ An unmanned spacecraft travels to mars. Mars has a lower strength of gravity than Earth. Where in the image is the spa

cecraft’s weight the greatest?

1 answer:

vlabodo [156]4 years ago

4 0

the unnamed spacecraft which travels to Mars, will have the greatest weight on the Earth.

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If a temperature increase from 21.0 ∘c to 35.0 ∘c triples the rate constant for a reaction, what is the value of the activation

Airida [17]

Answer:

59.077 kJ/mol.

Explanation:

From Arrhenius law: <em>K = Ae(-Ea/RT)</em>

where, K is the rate constant of the reaction.

A is the Arrhenius factor.

Ea is the activation energy.

R is the general gas constant.

T is the temperature.

At different temperatures:

<em>ln(k₂/k₁) = Ea/R [(T₂-T₁)/(T₁T₂)]</em>

k₂ = 3k₁ , Ea = ??? J/mol, R = 8.314 J/mol.K, T₁ = 294.0 K, T₂ = 308.0 K.

ln(3k₁/k₁) = (Ea / 8.314 J/mol.K) [(308.0 K - 294.0 K) / (294.0 K x 308.0 K)]

∴ ln(3) = 1.859 x 10⁻⁵ Ea

∴ Ea = ln(3) / (1.859 x 10⁻⁵) = 59.077 kJ/mol.

4 0

3 years ago

Are jellyfish unicellular or multicellular and why? I know the why part is a bit odd but my teacher requires it.

Ahat [919]

Answer:

multicellular

Explanation:

4 0

3 years ago

Read 2 more answers

A force acts on an object and moves it a certain distance. The product of the force and the distance is the

ladessa [460]

Answer is Work. Because work is done when force acts on object and the object displaces from position upto a distance...

7 0

3 years ago

A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solutio

Alja [10]

Answer:

Concentration of original solution = 1.66

Explanation:

We know that

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

We have given concentration of NaOH = 0.1678

Volume of NaOH = 19.88 mL = 0.01988 L

So moles of NaOH = volume x concentration of NaOH

= $0.01988\times 0.1678=0.00333mole$

Moles of $H_2SO_4$ in 10 mL of diluted solution = 1/2 x moles of NaOH

= $\frac{1}{2}$ x 0.00333 = 0.00166 mol

Moles of $H_2SO_4$ in 25 mL of original solution

= moles of H2SO4 in 250 mL of diluted solution

= $\frac{250}{10}$ x 0.00166 = 0.0415 mol

Concentration of original solution = $\frac{moles}{volume}$

= $\frac{0.0415}{0.025}=1.66$

8 0

3 years ago

Which parameters can you change to affect the rate of the reaction? in alphabetical order, list all that apply to this system.?

postnew [5]

Catalyst
Concentration
Temperature

6 0

4 years ago