Answer:
1) positive
2) carbocation
3) most stable
4) faster
Explanation:
A common test for the presence of alcohols can be achieved using the Lucas reagent. Lucas reagent is a mixture of concentrated hydrochloric acid and zinc chloride.
The reaction of Lucas reagent reacts with alcohols leading to the formation of an alkyl chloride. Since the reaction proceeds via a carbocation mechanism, tertiary alcohols give an immediate reaction. Once a tertiary alcohol is mixed with Lucas reagent, the solution turns cloudy almost immediately indicating an instant positive reaction.
Secondary alcohols may turn cloudy within five minutes of mixing the solutions. Primary alcohols do not significantly react with Lucas reagent obviously because they do not form stable carbocations.
Therefore we can use the Lucas reagent to distinguish between primary, secondary and tertiary alcohols.
Answer:
the other variable is also doubled
Explanation:
direct proportion, same thing has to happen to both variables
Answer:
0.125 mg
Explanation:
<em>The correct answer would be 0.125 mg</em>
<u>According to the conversion factor, one milligram of a sample is equivalent to one thousand micrograms of the same sample.</u>
milligram = 
microgram = 
Hence,
1 milligram = 1000 micrograms or 1 microgram =
milligram
Therefore, 125 micrograms will be:
125/1000 = 0.125 milligram
The answer is C as enzymes are biological catalysts that act on a substrate such as starch if the enzyme were amylase
hope that helps