Answer:
a. Rate = k [H2O+-OH][Br-]
Explanation:
For a reaction:
nA+xB→C+D
The rate of the reaction is:
Rate = [A]ⁿ[B]ˣ
Now, in a mechanism, the rate of the reaction depends of the slow step. In the problem:
H2O+-OH + Br-→ HOBr + H2O
And the rate is:
<h3>a. Rate = k [H2O+-OH][Br-]
</h3>
The best title for this note will be FEATURES AND APPLICATION OF ULTRASOUND.
All the points listed above are characteristics and uses of ultrasound. Ultrasound is defined as the sound wave which has frequency that is higher than the upper audible limit of human hearing. It is used in many fields including medical field. In the medical field, ultrasound is used as a diagnostics tool to treat many disease conditions.
B) Gas
Reason: Because Gas has te hhighest entropy?
Answer:
The most common position for an double bond in an unsaturated fatty acid is delta 9 (Δ⁹)
Explanation:
Unsaturated fatty acids are carboxylic acids which contains one or more double bonds. The chain length as well as the number of double bonds is written separated by a colon. The positions of the double bonds are specified starting from the carboxyl carbon, numbered as 1, by superscript numbers following a delta (Δ). For example, an 18-carbon fatty acid containing a single double bond between carbon number 9 and 10 is written as 18:1(Δ⁹).
In most monounsaturated fatty acids, the double bond is between C-9 and C-10 (Δ⁹), and the other double bonds of polyunsaturated fatty acids are generally Δ¹² and Δ¹⁵. This positioning is due to the nature of the biosynthesis of fatty acids. In the mammalian hepatocytes, double bonds are introduced easily into fatty acids at the Δ⁹ position, but cannot introduce additional double bonds between C-10 and the methyl-terminal end. However, plants are able to introduce these additional double bonds at the Δ¹² and Δ¹⁵ positions.
