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AlladinOne [14]
1 year ago
13

A severe thunderstorm, known as a supercell, forms. It begins in an area where cold, dry, polar air meets warm, moist, tropical

air, and the atmosphere is unstable. The wind coming into this storm begins to swirl, creating a swirling area of very low pressure. Which of the following is likely to occur in these conditions?
Chemistry
1 answer:
Andre45 [30]1 year ago
8 0

Answer:

Tornado

Explanation:

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Which of the following statements is true?
Anna007 [38]

Answer:

C. Lithium is most easily oxidized of the metals listed on the activity series and therefore it will most easily give electrons to metal cations

Explanation:

"Lithium" is a type of alkali metal that has a "single valence electron." Since it is a reactive element, it easily gives up an electron when it is combined with other elements. Such giving up of electron is meant to create compounds or bonds.

Among the common metals listed, "lithium" is the most easily oxidized. This means that it donates its electrons immediately. Such combination makes it exist as a<em> "cation"</em> or <em>"positively-charged."</em>

So, this explains the answer.

6 0
3 years ago
list examples of foliated and nonfoliated rocks explain the difference between the two metamorphic rocks
weqwewe [10]

Explanation:

Foliated metamorphic rocks such as gneiss, phyllite, schist and slate have a layered or banded appearance that is produced by exposure to heat. Non Foliated rocks such as hornfels, marble and quartzite does not have a layered or banded appearance

5 0
4 years ago
To draw a Lewis structure for a polyatomic ion, begin by calculating A, the available electrons, and N, the needed electrons. Wh
Mrac [35]

Answer:

N for chlorate ion is one

Explanation:

Because N is the number of electrons needed to form octet structure causing a negative charge of one, since it already has 25valence electrons

4 0
4 years ago
Molten zinc chloride can be electrolysed.
Crank

Answer: The products of electrolysis are Zn(l) and Cl_2 gas

Explanation:

Electrolysis of a subastance is breaking it into its constituents by the action of electrical current.  

In the electrolysis of molten zinc chloride, zinc metal is produced at the cathode which is a negative electrode and chlorine gas produces as the anode which is a positive electrode.

ZnCl_2(l)\rightarrow Zn^{2+}+2Cl^-

At anode : 2Cl^-(l)\rightarrow 2e^-+Cl_2(g)

At cathode : Zn^{2+}(l)+2e^-\rightarrow Zn(l)

5 0
3 years ago
Find the enthalpy of neutralization of HCl and NaOH. 137 cm3 of 2.6 mol dm-3 hydrochloric acid was neutralized by 137 cm3 of 2.6
liraira [26]

Answer : The correct option is, (D) 89.39 KJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole

\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole

The balanced chemical reaction will be,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.3562 mole of HCl neutralizes by 0.3562 mole of NaOH

Thus, the number of neutralized moles = 0.3562 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = 137ml+137ml=274ml

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 274ml=274g

Now we have to calculate the heat absorbed during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

c = specific heat of water = 4.18J/g^oC

m = mass of water = 274 g

T_{final} = final temperature of water = 325.8 K

T_{initial} = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

q=274g\times 4.18J/g^oC\times (325.8-298)K

q=31839.896J=31.84KJ

Thus, the heat released during the neutralization = -31.84 KJ

Now we have to calculate the enthalpy of neutralization.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of neutralization = ?

q = heat released = -31.84 KJ

n = number of moles used in neutralization = 0.3562 mole

\Delta H=\frac{-31.84KJ}{0.3562mole}=-89.39KJ/mole

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 89.39 KJ/mole

3 0
4 years ago
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