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3 years ago

Which of the following statements is true?

Chemistry

1 answer:

Anna007 [38]3 years ago

6 0

Answer:

C. Lithium is most easily oxidized of the metals listed on the activity series and therefore it will most easily give electrons to metal cations

Explanation:

"Lithium" is a type of alkali metal that has a "single valence electron." Since it is a reactive element, it easily gives up an electron when it is combined with other elements. Such giving up of electron is meant to create compounds or bonds.

Among the common metals listed, "lithium" is the most easily oxidized. This means that it donates its electrons immediately. Such combination makes it exist as a<em> "cation"</em> or <em>"positively-charged."</em>

So, this explains the answer.

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The electron configuration for aluminum (Al) is shown below:

Serjik [45]

Answer:

It is the third choice

Explanation:

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3 0

4 years ago

OCAS GAME

makkiz [27]

ok so this was really confusing, but i think i know the answer. D. ...hairy and ancient hermit crabs and swift, darting minnows and sometimes a

crumbling sand dollar.

7 0

4 years ago

Which of the following has the strongest magnetic field?

wariber [46]

Answer:

Jupiter

Explanation:

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3 years ago

Limiting Reactants—————-

denis-greek [22]

Answer:

21.8 grams.

Explanation:

Molar mass data from a modern periodic table:

Mg: 24.301;
O: 15.999.

How many moles of MgO will be produced if Mg is the limiting reactant?

Number of moles of Mg:

$\displaystyle n = \frac{m}{M} = \frac{16.3}{24.301} = 0.670644\;\text{mol}$ .

The ratio between the coefficient of Mg and that of MgO is 2:2. Two moles of Mg will make two moles of MgO. 0.670644 moles of MgO will be produced if Mg is the limiting reactant.

How many moles of MgO will be produced if O₂ is the limiting reactant?

Number of moles of O₂:

$\displaystyle n = \frac{m}{M} = \frac{4.33}{15.999} = 0.270642\;\text{mol}$ .

The ratio between the coefficient of O₂ and that of MgO is 1:2. One mole of O₂ will make two moles of MgO. $2\times 0.270642 = 0.541284\;\text{mol}$ of MgO will be produced if O₂ is in excess.

How many moles of MgO will be produced?

0.541284 is smaller than 0.670644. Only 0.541284 moles of MgO will be produced since O₂ will run out before all 16.3 grams of Mg is consumed.

What's the mass of 0.541284 moles of MgO?

Formula mass of MgO:

$24.301 + 15.999 = 40.300\;\text{g}\cdot\text{mol}^{-1}$ .

Mass of 0.541284 moles of MgO:

$m = n \cdot M = 0.541284\times 40.300 = 21.8\;\text{g}$ .

7 0

3 years ago

Answer questions 2 and 3

nlexa [21]

Answer:

2:a-heterogenous

b-homogenous

c-heterogenous

d-heterogenous with water

3:Filtration is used to separate insoluble particles from a solution

Distillation is used to separate liquids with close but different boiling points e.g water and ethanol

Explanation:

2: homogenous mixtures form a uniform layer meaning that a mixture containing more than one layer is heterogenous

4 0

4 years ago