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3 years ago

Which of the following statements is true?

Chemistry

1 answer:

Anna007 [38]3 years ago

6 0

Answer:

C. Lithium is most easily oxidized of the metals listed on the activity series and therefore it will most easily give electrons to metal cations

Explanation:

"Lithium" is a type of alkali metal that has a "single valence electron." Since it is a reactive element, it easily gives up an electron when it is combined with other elements. Such giving up of electron is meant to create compounds or bonds.

Among the common metals listed, "lithium" is the most easily oxidized. This means that it donates its electrons immediately. Such combination makes it exist as a "cation" or "positively-charged."

So, this explains the answer.

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Why are rocks not alive

Liula [17]

What Are Living Rocks? Rocks themselves are not alive. But in a coral reef rock-like lime substance is continually produced from the skeletons of dead rock corals and the shells of mussels and other creatures which are bound together by sponges and calcareous algae.

but tbh I have no idea lol!

5 0

3 years ago

Read 2 more answers

How many electrons are in an ion of calcium (Ca2+)? A. 2 B. 18 C. 0 D. 22

Elanso [62]

B 18 is the answer ......

7 0

2 years ago

The 225 g FeCl2 is about 1.8 moles.

Lyrx [107]

Answer:

$4 \frac{mol}{l}$

Explanation:

From the question, we have been asked to find the molarity of FeCl2 having a volume of 450 mL,

We have been provided with 225 g which is proportional to 1.8 moles.

We know that molarity of any solution should be in mol/L.

1 mole contained in 1 L means it has a molarity of 1 mol/L

Let's convert 450 mL to Litres which is,

$\frac{450}{1000} litres$

= 0.450 L

Thus,

1 mole is contained in 1L

x moles are contained in 0.450 L

Hence,

x mole/molarity = {1 mole x 1 L}/{0.450 L}

= 4 mol/L

Therefore 4 mol/L is the molar concentration.

5 0

1 year ago

What is the mass in grams of BaCl2 that is needed to prepare 200 mL of a 0.500 M solution

DENIUS [597]

Answer:

= 20.82 g of BaCl2

Explanation:

Given,

Volume = 200 mL

Molarity = 0.500 M

Therefore;

Moles = molarity × volume

= 0.2 L × 0.5 M

= 0.1 mole

But; molar mass of BaCl2 is 208.236 g/mole

Therefore; 0.1 mole of BaCl2 will be equivalent to;

= 208.236 g/mol x 0.1 mol

= 20.82 g

Therefore, the mass of BaCl2 in grams required is 20.82 g

6 0

2 years ago

8. Select the lattice energy for rubidium chloride from the following data (in kJ/mol]

yKpoI14uk [10]

Answer:

Option C

Explanation:

The chemical reactions which are involved while solving this problem is there in the file attached and each chemical reaction is represented by a certain equation number

Lattice energy for rubidium chloride ( RbCl) is represented by the equation 6

Equation 1 represents the change in enthalpy for formation of RbCl

Equation 2 represents the sublimation reaction of rubidium

Equation 3 represents the ionization enthalpy of rubidium

Equation 4 represents the enthalpy of atomization of chlorine which means it describes the bond enthalpy of Cl2 molecule

Equation 5 represents the electron affinity of chlorine

To find the lattice energy for RbCl we have to use all the equations from 1 to 5 so that at last we get the equation 6

We have to perform operations such as

Equation 1 - equation 2 - equation 3 - equation 4 - equation 5

By performing these operations the intermediate compounds gets cancelled and at last we get equation 6

So Equation 1 ≡ ΔH $_{f}$ = -431 kJ/mol

Equation 2 ≡ Rb(s) ---> Rb(g) = 85.8 kJ/mol

Equation 3 ≡ IE1(Rb) = 397.5 kJ/mol

Equation 4 ≡ BE(Cl2) = 226 kJ/mol

Equation 5 ≡ Electron Affinity Cl = -332 kJ/mol

Value corresponding to the equation 6 will be the value of lattice energy of RbCl and the value is -695·3 kJ/mol

∴ Lattice energy for rubidium chloride is approximately -695 kJ/mol

4 0

3 years ago