P ( work/ senior ) = 0.14
The attached table
required
P ( work/ senior )
This is calculated using:
P ( work/ senior ) = n ( work/ senior )/ n ( senior ).
n ( work/ senior ) = 5
n ( senior ) = 25 + 5 + = 35
So:
P ( work/ senior ) = 5/35
P ( work/ senior ) = 0.14
Add 25+5+5 (because that is all the numbers in the 'Seniors' row) and then take the 5 that is in the 'Work' column and put that over 25. (5/25 fraction as a percent is 14).
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Answer:
2800
Step-by-step explanation:
round 278 to 280
then round 11 to 10
then times the 2 answers together
2)
4x-10y=12
Subtract 4x from each side.
-10y=-4x+12
Divide both sides by -10
y=2/5x-6/5
3)
13=1/6y+2x
Subtract 2x from each side.
-2x+13=1/6y
Multiply both sides by 6.
-12x+78=y
Flip it around.
y=-12x+78
Hope this helps!
Answer:
The probability that a student is an undergraduate student, given that the student received a plus grade is 0.92
Step-by-step explanation:
The conditional probability of an event <em>B</em> given that another event <em>A</em> has already occurred is:

Denote the events as follows:
<em>X</em> = a students is a graduate
<em>Y </em>= a students is a under-graduate
+ = a student received one or more plus grades
- = a student received one or more minus grades
Consider the tree diagram below.
According to the tree diagram, the probability that a student is an undergraduate student, given that the student received a plus grade is:
P (+ | Y) = 0.92
Thus, the probability that a student is an undergraduate student, given that the student received a plus grade is 0.92.
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