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1 year ago

12

Is work done whenever you hold a heavy object for a long time?

1 answer:

AnnZ [28]1 year ago

7 0

No, work is not done whenever you hold a heavy object for a long time

<h3>What is work done ?</h3>

The result of a force's displacement and its component of force exerted by the object in the direction of displacement is what is known as the force's work. When we push a block with some force, the body moves quickly and work is completed.

No work, as that term is used here, is done until the object is moved in some way and a component of the force travels along the path that the object is moved. Because there is no displacement when holding a heavy object still, energy is not transferred to it.

Learn more about Work done here:

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The enthalpy of vaporization of liquid water at 100°C is 2257 kJ/kg. Determine the enthalpy for apordato of iuod eeat capacity o

igomit [66]

Explanation:

The given data is as follows.

$T_{1} = 100^{o}C$ , $T_{2} = 10^{o}C$

$\Delta H_{vap1}$ = 2257 kJ/kg, $\Delta H_{vap2}$ = ?

For water, $C_{p}$ = 4.184 $kJ/kg ^{o}C$

Formula to calculate heat of vaporization is as follows.

$\Delta H_{vap1} - \Delta H_{vap2}$ = $C_{p}(T_{1} - T_{2})$

Hence, putting the values into the above formula as follows.

$\Delta H_{vap1} - \Delta H_{vap2}$ = $C_{p}(T_{1} - T_{2})$

$2257 kJ/kg - \Delta H_{vap2}$ = $4.184 kJ/kg ^{o}C (100 - 10)^{o}C$

$\Delta H_{vap2}$ = 2257 kJ/kg - 376.56 kJ/kg

= 1880.44 kJ/kg

Thus, we can conclude that enthalpy of liquid water at $10^{o}C$ is 1880.44 kJ/kg.

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3 years ago

W + BgCz2 --> WCz + Bg<br> Balance this equation

yanalaym [24]

Answer: W + BgCz2 arrow WCz + Bg

2 W + BgCz2 arrow 2 WCz + Bg

Explanation:

Cz has 2 so you balcne the other side of WCz.

Since you Balcanes the Cz you changed the W and you Balcanes the other W on the left side.

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3 years ago

Why do teapots have highly polished surface

Natali [406]

Good conductors of electricity and heat, form cations by loss of electrons,

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Explanation:

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3 years ago

Which is the dependent variable in an experiment? 1.what I observe. 2. what I keep the same 3.What I change in the experiment. H

shtirl [24]

Answer:

1.what I observe.

Explanation:

The dependent variable in an experiment is what is being observed in the experimental procedure.

This variable is the one that is closely tied to the effects originating from changing the independent variables.

Independent variables are the ones that cause the observation being studied.
The effects produced and then studied are the dependent variables.

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3 years ago