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2 years ago

Formula of sodium bicarbonateplease help me with this

Chemistry

1 answer:

Stels [109]2 years ago

5 0

Answer:

NaHCO₃

Explanation:

Sodium bicarbonate (baking soda) is a chemical compound with the formula NaHCO₃.

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2 years ago

If 1.0 mole of CH4 and 2.0 moles of Cl2 are used in the reaction CH4 + 4Cl2 => CCl4 + 4HCl then which of these statements is

nikklg [1K]

Answer:

B,C,D

Explanation:

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2 years ago

9. What lab equipment is used to spread heat when heating to prevent glassware from cracking

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2 years ago

The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In t

const2013 [10]

Answer:

$\boxed{\text{47.4 g}}$

Explanation:

We are given the mass of two reactants, so this is a limiting reactant problem.

We know that we will need mases, moles, and molar masses, so, let's assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r: 17.03 32.00 18.02

4NH₃ + 5O₂ ⟶ 4NO + 6H₂O

m/g: 70.1 70.1

Step 1. Calculate the moles of each reactant

$\text{Moles of CO } = \text{70.1 g} \times \dfrac{\text{1 mol}}{\text{17.03 g}} = \text{4.116 mol}\\\\\text{Moles of H$_{2}$O} = \text{70.1 g} \times \dfrac{\text{1 mol}}{\text{32.00 g}} = \text{2.191 mol}$

Step 2. Identify the limiting reactant

Calculate the moles of H₂O we can obtain from each reactant.

From NH₃:

The molar ratio of H₂O:NH₃ is 6:4.

$\text{Moles of H$_{2}$O} = \text{4.116 mol NH$_{3}$} \times \dfrac{\text{6 mol H$_{2}$O}}{\text{4 mol NH$_{3}$}} = \text{6.174 mol H$_{2}$O}$

From O₂:

The molar ratio of H₂O:O₂ is 6:5.

$\text{Moles of H$_{2}$O} = \text{2.191 mol O$_{2}$} \times \dfrac{\text{6 mol H$_{2}$O}}{\text{5 mol O$_{2}$}} = \text{2.629 mol H$_{2}$O}$

O₂ is the limiting reactant because it gives the smaller amount of H₂O.

Step 3. Calculate the theoretical yield.

$\text{Theor. yield } = \text{2.629 mol H$_{2}$O}\times \dfrac{\text{18.02 g H$_{2}$O}}{\text{1 mol H$_{2}$O}} = \textbf{47.4 g H$_{2}$O}\\\\\text{The maximum yield of H$_{2}$O is }\boxed{\textbf{47.4 g}}$

6 0

2 years ago

Imagine that small pieces of the metals copper, magnesium and iron are placed in three test tubes labeled A, B, and C, respectiv

Marizza181 [45]

A) Cu

Cu + 2HCl --> CuCl2 + H2(g)

Products predicted: Copper(II) choloride and hydrogen gas

B) Mg

Mg + 2HCl --> MgCl2 + H2

Products predicted: magnesium chloride + hygrogen gas

C) Fe

Fe +2 HCl -> FeCl2 + H2, or
2Fe +6 HCl -> 2FeCl3 + 3H2

Products predicted: Iron(II) chloride, iron (III) chloride and hydrogen gas.

8 0

3 years ago

Formula of sodium bicarbonateplease help me with this​

Formula of sodium bicarbonateplease help me with this