States that when a gas is held at a constant temperature and mass in a closed container, the volume and pressure vary inversely. The equation to use is P1V1=P2V2.
Given
V1=200mL×1L1000mL=0.2 L
P1=700 mmHg
V2=100mL×1L1000mL=0.1 L
Unknown
P2
Equation
P1V1=P2V2
Solution
Rearrange the equation to isolate P2 and solve.
P2=P1V1V2
P2=(700mmHg×0.2L)0.1L=1400 L, which must be rounded to 1000 L because all of the measurements have only one significant figure.
For an arrangement of electrons to be nonpolar in a molecule they need to have equal electron charges.
Answer:
10.76 grams
Explanation:
Given that the amount of 
is 25.0 grams.
Mass of 1 mole of = 158 grams
The number of atoms in 1 mole of is 4.
Mass of oxygen in 1 mole of = 16\times 4 = 68 grams.
Here, 158 grams of has 68 grams of oxygen
So, the amount of oxygen in 1 gram of = 68/158 grams
Therefore, the amount of oxygen in 1 gram of = 
grams
=10.76 grams
Hence, 25 grams of has 10.76 grams of oxygen.
Color change, formation of a precipitation, formation of a gas, odor change, temperature change
Answer: (a) K *[A][B]^2
(b) The answer is B
Explanation:
A)
Step1:A+B<--> C (fast)
Step2: B+C→D(slow)
Rate depends on slowest step.
so,
rate = k' [B][C] ...eqn 1
But C is intermediate.so use step 1
Since 1st step is an equilibrium,
Kc = [C] /[A][B]
so,
[C] = Kc [A][B] ...eqn 2
put eqn 2 in eqn 1
rate = k' *[B] * Kc [A][B]
= k'Kc*[A][B]^2
= K *[A][B]^2 {writing k'Kc = K}
Answer: K *[A][B]^2
B)
Answer is B
Since rate depends on slowest step.
if slowest step is:
X2Y2+Z2→X2Y2Z+Z
then only,
rate= k[X2Y2][Z2]
Answer: B
