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Serhud [2]
3 years ago
11

Formula of sodium bicarbonateplease help me with this​

Chemistry
1 answer:
Stels [109]3 years ago
5 0

Answer:

NaHCO₃

Explanation:

Sodium bicarbonate (baking soda) is a chemical compound with the formula NaHCO₃.

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A reaction of heating potassium permanganate produces
DIA [1.3K]

Answer: 1.6g

Explanation:

8 0
3 years ago
Approximately 0.0972 g of carbon dioxide gas can be dissolved in 100 mL of water at 40°C expressed in terms of parts per million
IRISSAK [1]

Answer:

972 ppm

Explanation:

Percent (parts per hundred - pph), parts per million & parts per billion are ratios of a component of interest divided by total mix of several components.

That is, given 28%, this says 28/100, or 28ppm says 28/10⁶, or 28ppb says 28/10⁹.

To convert from the given (=> any of the three concentration ratios) simply multiply (X) where you wish to go.

Examples:

  • Convert 35% to ppm and ppb
  • 35% = (35/100) x 10⁶ppm = 3.5 x 10⁵ ppm
  • _______________________________
  • Convert 43 ppm to %
  • 43 ppm = (43/10⁶) x 100% = 4.3 x 10³%
  • ______________________________
  • Convert 81 ppb to ppm
  • 81 ppb = (81/10⁹) x 10⁶ppm = 8.1 x 10⁻² ppm

Notice how each 'Given' is expressed as a ratio of amount/100 (given pph or %),  or amount/10⁶ (given ppm) or amount/10⁹ (given ppb). All you need to do here is multiply by where you want to go.

=> Given % = (amount/100) x 10⁶ => ppm

=> Given ppm = (amount/10⁶) x 100 => %, or pph

=> Given ppb = (amount/10⁹) x 10⁶ => ppm

Given ratio x 100 = %, or x 10⁶ => ppm or x 10⁹ => ppb

Your Problem:

Given = (0.0972g/100g) x 10⁶ppm = 972 ppm

or, if you wish ppb => (0.0972g/100g) x 10⁹ppb = 972,000 ppb

5 0
3 years ago
Will give brainly
kicyunya [14]

Answer:

Ch4 + 2O2 ----> CO2 + 2H2O

Explanation:

Ch4 has 4H, 1C

O2 has 2 O2

CO2 has 1 C, 2O

H2O has 1 H, 2O

you need to add 2 to O2 to balance it. Add 2 to H2O to balance the H and O

3 0
3 years ago
Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:
posledela

Answer: The value of the equilibrium constant Kc for this reaction is 3.72

Explanation:

Equilibrium concentration of HNO_3 = \frac{15.5g}{63g/mol\times 9.5L}=0.026M

Equilibrium concentration of NO = \frac{16.6g}{30g/mol\times 9.5L}=0.058M

Equilibrium concentration of NO_2 = \frac{22.5g}{46g/mol\times 9.5L}=0.051M

Equilibrium concentration of H_2O = \frac{189.0g}{18g/mol\times 9.5L}=1.10M

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c  

For the given chemical reaction:

2HNO_3(aq)+NO(g)\rightarrow 3NO_2(g)+H_2O(l)

The expression for K_c is written as:

K_c=\frac{[NO_2]^3\times [H_2O]^1}{[HNO_3]^2\times [NO]^1}

K_c=\frac{(0.051)^3\times (1.10)^1}{(0.026)^2\times (0.058)^1}

K_c=3.72

Thus  the value of the equilibrium constant Kc for this reaction is 3.72

5 0
3 years ago
Binary systems account for approximately what proportion of star systems in the universe
irinina [24]
One third; or 33.34%
5 0
4 years ago
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