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3 years ago

At 60 °C the value of Kw is 9.5 x 10-14.

Chemistry

1 answer:

andre [41]3 years ago

6 0

Answer:

Explanation:

Ba(OH)₂ is a strong base that dissociates according to the following equation.

Ba(OH)₂(aq) → Ba²⁺(aq) + 2 OH⁻(aq)

The molar ratio of Ba(OH)₂ to OH⁻ is 1:2. Then, the concentration of OH⁻ is 2 × 5.00 × 10⁻² M = 0.100 M

The ionic product of water (Kw) is:

Kw = 9.5 × 10⁻¹⁴ = [H⁺].[OH⁻] = [H⁺].(0.100)

[H⁺] = 9.5 × 10⁻¹³ M

The pH is

pH = -log [H⁺] = -log 9.5 × 10⁻¹³ = 12

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A sample of xenon gas occupies a volume of 6.80 L at 52.0°C and 1.05 atm. If it is desired to increase the volume of the gas sam

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Answer:

207.03°C

Explanation:

The following data were obtained from the question:

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T1 (initial temperature) = 52.0°C = 52 + 273 = 325K

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Using the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas sample can be obtained as follow:

P1V1/T1 = P2V2/T2

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Cross multiply to express in linear form as shown below:

1.05 x 6.8 x T2 = 325 x 1.34 x 7.87

Divide both side by 1.05 x 6.8

T2 = (325 x 1.34 x 7.87) /(1.05 x 6.8)

T2 = 480.03K

Now, let us convert 480.03K to a number in celsius scale. This is illustrated below:

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3 years ago

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Explanation:

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3 years ago

2Al + 6HCl → 2AlCl3 + 3H2<br> If 85.0 grams of HCl react, how many moles of H2 are produced?

Murrr4er [49]

Answer:

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Explanation:

Step 1: Write the balanced equation

2 Al + 6 HCl → 2 AlCl₃ + 3 H₂

Step 2: Calculate the moles corresponding to 85.0 g of HCl

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Step 3: Calculate the number of moles of H₂ produced from 2.33 moles of HCl

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2.33 mol HCl × 3 mol H₂/6 mol H₂ = 1.17 mol H₂

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2 years ago