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natita [175]
3 years ago
9

At 60 °C the value of Kw is 9.5 x 10-14.

Chemistry
1 answer:
andre [41]3 years ago
6 0

Answer:

12

Explanation:

Ba(OH)₂ is a strong base that dissociates according to the following equation.

Ba(OH)₂(aq) → Ba²⁺(aq) + 2 OH⁻(aq)

The molar ratio of Ba(OH)₂ to OH⁻ is 1:2. Then, the concentration of OH⁻ is 2 × 5.00 × 10⁻² M = 0.100 M

The ionic product of water (Kw) is:

Kw = 9.5 × 10⁻¹⁴ = [H⁺].[OH⁻] = [H⁺].(0.100)

[H⁺] = 9.5 × 10⁻¹³ M

The pH is

pH = -log [H⁺] = -log 9.5 × 10⁻¹³ = 12

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Explanation:

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2 years ago
If the initial [NO2] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M. If the initial is 0.260 , it
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The question is incomplete, here is the complete question:

At elevated temperature, nitrogen dioxide decomposes to nitrogen oxide and oxygen gas

NO_2\rightarrow NO+\frac{1}{2}O_2

The reaction is second order for NO_2 with a rate constant of 0.543M^{-1}s^{-1} at 300°C. If the initial [NO₂] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M

a) 1.01    b) 5.19     c) 0.299      d) 0.0880     e) 3.34

<u>Answer:</u> The time taken is 5.19 seconds

<u>Explanation:</u>

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.543M^{-1}s^{-1}

t = time taken  = ?

[A] = concentration of substance after time 't' = 0.150 M

[A]_o = Initial concentration = 0.260 M

Putting values in above equation, we get:

0.543=\frac{1}{t}\left (\frac{1}{(0.150)}-\frac{1}{(0.260)}\right)\\\\t=5.19s

Hence, the time taken is 5.19 seconds

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Answer:

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Explanation:

true

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