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In-s [12.5K]
2 years ago
8

What is the stable form of nitrogen?

Chemistry
1 answer:
shusha [124]2 years ago
3 0

The stable form of Nitrogen is N-14 and N-15.

  1. Nearly all proteins contain nitrogen, which is crucial for biochemical processes as well as industrial processes.
  2. Due to its capacity to form a triple bond with both itself and other elements, nitrogen forms strong bonds. As a result, nitrogen compounds contain a lot of energy. Little was known about nitrogen before one hundred years ago.
  3. More than 99 percent of all nitrogen found on Earth is found in the most abundant form of nitrogen, nitrogen-14. non-radioactive and stable, it is a substance.
  4. The most widely used form of nitrogen, 14, is used in biochemicals, biomedical research, food preservation, and agricultural practices.
  5. The second stable state of nitrogen is nitrogen-15. It is frequently employed in medical preservation and research.

To learn more about nitrogen compounds-

<u>brainly.com/question/25808871</u>

#SPJ4

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Idk what the answer is, can someone help?
nignag [31]
2

2

3

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4 years ago
Hydrogen sulfide,H2S, is a very toxic gas with a smell of rotten eggs. using the following: H2S+3/2 O2=SO2+H2O H2+1/2O2=H2O S+O2
Serga [27]

Answer:

ΔH = -20kJ

Explanation:

The enthalpy of formation of a compound is defined as the change of enthalpy during the formation of 1 mole of the substance from its constituent elements. For H₂S(g) the reaction that describes this process is:

H₂(g) + S(g) → H₂S(g)

Using Hess's law, it is possible to sum the enthalpies of several reactions to obtain the change in enthalpy of a particular reaction thus:

<em>(1) </em>H₂S(g) + ³/₂O₂(g) → SO₂(g) + H₂O(g) ΔH = -519 kJ

<em>(2) </em>H₂(g) + ¹/₂O₂(g) → H₂O(g) ΔH = -242 kJ

<em>(3) </em>S(g) + O₂(g) → SO₂(g) ΔH = -297 kJ

The sum of -(1) + (2) + (3) gives:

<em>-(1) </em>SO₂(g) + H₂O(g) → H₂S(g) + ³/₂O₂(g) ΔH = +519 kJ

<em>(2) </em>H₂(g) + ¹/₂O₂(g) → H₂O(g) ΔH = -242 kJ

<em>(3) </em>S(g) + O₂(g) → SO₂(g) ΔH = -297 kJ

<em>-(1) + (2) + (3): </em><em>H₂(g) + S(g) → H₂S(g) </em>

<em>ΔH =</em> +519kJ - 242kJ - 297kJ = <em>-20 kJ</em>

<em />

I hope it helps!

5 0
3 years ago
How many atoms are there in 10.2 moles of Phosphorous?​
nikdorinn [45]

There are 2.06 x 10²⁴ atoms

<h3>Further explanation </h3>

The mole is the number of particles (atoms, molecules, ions)contained in a substance

1 mol = 6.02.10²³  particles

Moles can also be determined from the amount of substance mass and its molar mass

  • number of atoms :

\tt 10.2\times 6.02\times 106{23}=2.06\times 10^{24}

5 0
3 years ago
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