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pychu [463]
3 years ago
14

The number of molecules in 1.0 mole of H2O is the same as in one mole of O2.

Chemistry
2 answers:
zaharov [31]3 years ago
8 0
True. A mole of anything has the same amount of molecules. 1 mole = 6.022 x 1023 molecules 
Mrrafil [7]3 years ago
7 0

Answer:

true

Explanation:

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Explain why warm nitric acid is used​
Schach [20]

Answer:

Lead is added to warm dilute nitric acid. When the carbonate has reacted with the warm acid, more carbonate is added until the carbonate is in excess.

Explanation:

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3 years ago
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(Please Help!) Aluminum reacts with oxygen to produce aluminum oxide (AI203). The balanced chemical equation for this reaction i
andriy [413]

#1

Moles of Oxygen =3

Molecules:-

  • 3×Avagadro no
  • 3(6.022×10²³)
  • 18.066×10²³
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#2

Its because according to law of conservation of mass- Mass is neither created nor destroyed

AS ITS BALANCED SO BOTH SIDES ARE SAME .

HENCE THEY OBEY

5 0
2 years ago
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What is produced when 50mLs of carbon and 30mLs of oxygen react
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50ml of carbon dioxide.

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3 0
3 years ago
The reaction of ethane gas (C2H6) with chlorine gas produces C2H5Cl as its main product (along with HCl). In addition, the react
Kazeer [188]

Answer:

The percent yield of  chloro-ethane in the reaction is 82.98%.

Explanation:

C_2H_6+Cl_2\rightarrow C_2H_5Cl+HCl

Moles of ethane = \frac{300.0 g}{30 g/mol}=10 mol

Moles of chlorine gases =\frac{650.0 g}{71 .0 g/mol}=9.1549 mol

As we can see that 1 mol of ethane react with 1 mole of chlorine gas.the 10 moles will require 10 mole of chlorine gas, but only 9.1549 moles of chlorine gas is present.

This means that chlorine gas is in limiting amount and amount of formation of chloro-ethane will depend upon amount of chlorine gas.

According to reaction , 1 mol of chloro ethane gives 1 mol of chloro-ethane.

Then 9.1549 moles of chlorien gas will give:

\frac{1}{1}\times 9.1549 mol=9.1549 mol of chloro-ethane

Mass of 9.1549 moles of chloro-ethane:

9.1549 mol × 64.5 g/mol = 590.4910 g

Theoretical yield of  chloro-ethane: 590.4910 g

Given experimental yield of chloro-ethane: 490.0 g

\% Yield=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

\%Yield (C_2H_5Cl)=\frac{490.0 g}{590.4910 g}\times 100=82.98\%

The percent yield of  chloro-ethane in the reaction is 82.98%.

6 0
3 years ago
7. What determines what type of element an atom is?
frozen [14]
The amount of protons
3 0
3 years ago
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