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3 years ago

15

as u move down the levels of classification the number of classification the number of organisms in the level decrease or increa

se?

2 answers:

notsponge [240]3 years ago

4 0

Answer:

decrease

Explanation:

alexira [117]3 years ago

4 0

The number species decreases in each group moving down the levels of classification.

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When h2o is added to a compound in a chemical equation, a new compound can be formed via what type of reaction?

Scorpion4ik [409]

When water is added to a compound in a chemical equation, a new compound can be formed, it is called a hydrolysis reaction.

<h3>What is hydrolysis reaction?</h3>

There are so many kinds of reaction in chemistry we know that a chemical reaction occurs between reactant molecules in order to yield products in the reactants.

The hydrolysis reaction is a breaking up reaction. In a hydrolysis reaction, water is used to break up a molecule. Hence in a hydrolysis reaction water could be regarded as one of the reactants in the reactions going on in the system.

We know that a hydrolysis is a reaction in which water reacts with another reactant molecule to yield products in the reaction. Thus, when water is added to a compound in a chemical equation, a new compound can be formed, it is called a hydrolysis reaction.

Learn more about hydrolysis:brainly.com/question/12237250

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5 0

2 years ago

What claim is being made?

dangina [55]

The correct answer is c

7 0

4 years ago

Read 2 more answers

The rate constant k for a certain reaction is measured at two different temperatures temperature 376.0 °c 4.8 x 108 280.0 °C 2.3

9966 [12]

Answer:

The activation energy for this reaction = 23 kJ/mol.

Explanation:

Using the expression,

$\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )$

Where,

$k_1\ is\ the\ rate\ constant\ at\ T_1$

$k_2\ is\ the\ rate\ constant\ at\ T_2$

$E_a$ is the activation energy

R is Gas constant having value = 8.314×10⁻³ kJ / K mol

$k_2=2.3\times 10^8$

$T_2=280\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (280 + 273.15) K = 553.15 K

$T_2=553.15\ K$

$k_1=4.8\times 10^8$

$T_1=376\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (376 + 273.15) K = 649.15 K

$T_1=649.15\ K$

So,

$\left(\ln \left(\:\frac{4.8\times \:\:\:10^8}{2.3\times \:\:\:10^8}\right)\right)\:=-\frac{E_a}{8.314\times \:10^{-3}\ kJ/mol.K}\times \:\left(\frac{1}{649.15\ K}-\frac{1}{553.15\ K}\right)$

$E_a=-\frac{10^{-3}\times \:8.314\ln \left(\frac{10^8\times \:4.8}{10^8\times \:2.3}\right)}{-\frac{96}{359077.3225}}\ kJ/mol$

$E_a=-\frac{\frac{8.314\ln \left(\frac{4.8}{2.3}\right)}{1000}}{-\frac{96}{359077.3225}}\ kJ/mol$

$E_a=22.87\ kJ/mol$

<u>The activation energy for this reaction = 23 kJ/mol.</u>

6 0

3 years ago

Jose mixed two clear liquids together in a beaker in equal amounts. Jose measured the mass. The mass of the two combined solutio

Dmitrij [34]

Who cares. Joe can solve his own problem instead of making people do it. (This was not toward you. This was supposed to be funny)

5 0

3 years ago

What mass of oxygen is required to completely react with 2 moles of ch4

Firlakuza [10]

The balanced reaction that describes the reaction between methane and oxygen to produce water and carbon dioxide is expressed CH4 + 2 O2 = CO2 +2H2O. Hence for 2 moles of methane used, 4 moles of oxygen are needed to react completely.

7 0

3 years ago