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blsea [12.9K]
3 years ago
15

Which is most likely why many scientists reject the cold fusion theory?

Chemistry
1 answer:
Masja [62]3 years ago
8 0
The answer is D. The cold fusion theory was first brought about by Stanley Pons and Martin Fleischmann in 1989. They claimed that their unintended experiment has produced enormous amounts energy at room temperatures that could only be explained by cold fusion theory. The experiment involved the electrolysis of heavy water (with deuterium rather than hydrogen isotope) on a palladium (Pd) electrode. Their claims had brought immense attention by scientists, however, subsequent replicative experiments attempts failed and some discredited the initial experiment.
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Photosynthesis uses all of the following except __ to make food ?<br>​
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If aluminum has a mass of 22.3 g, how many liters of oxygen gas are required at STP?
IceJOKER [234]

Answer:

27.8

Explanation:

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Are diamonds flammable?
Debora [2.8K]
A match-head is flammable, but you have to get it up to its ignition temperature first.

A diamond is flammable, but its ignition temperature is astronomical and
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4 0
3 years ago
Read 2 more answers
A solution contains an unknown amount of dissolved magnesium. Addition of
Scrat [10]

Taking into account the reaction stoichiometry, 2.13 grams of magnesium was dissolved in the solution.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Mg²⁺(aq) + Na₂CO₃(aq) → MgCO₃(s) + 2 Na⁺(aq)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Mg²⁺: 1 mole
  • Na₂CO₃: 1  mole
  • MgCO₃: 1 mole
  • Na⁺: 2 moles

The molar mass of the compounds is:

  • Mg²⁺: 24.3 g/mole
  • Na₂CO₃: 106 g/mole
  • MgCO₃: 84.3 g/mole
  • Na⁺: 23 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Mg²⁺: 1 mole ×24.3 g/mole= 24.3 grams
  • Na₂CO₃: 1 mole ×106 g/mole= 106 grams
  • MgCO₃: 1 mole ×84.3 g/mole=84.3 grams
  • Na⁺: 2 moles ×23 g/mole= 46 grams

<h3>Mass of magnesium dissolved</h3>

The following rule of three can be applied: If by reaction stoichiometry 1 mole of Na₂CO₃ react with 24.3 grams of magnesium, 0.0877 moles of Na₂CO₃ react with how much mass of magnesium?

mass of magnesium=\frac{0.0877 moles of Na_{2}C O_{3}x24.3 grams of magnesium }{1 mole of Na_{2}C O_{3}}

<u><em>mass of magnesium= 2.13 grams</em></u>

Finally, 2.13 grams of magnesium was dissolved in the solution.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

4 0
3 years ago
If we react 30 grams of ethane (C2H6 ) with 320 grams of oxygen, how many grams of carbon dioxide would we make
V125BC [204]

The mass of carbon dioxide that would be made by reacting 30 grams C2H6 with 320 grams O2 will be 80 grams

From the balanced equation of the reaction:

2C_2H_6+7O_2---4CO_2+6H_2O

The mole ratio of C2H6 to O2 is 2:7.

  • Mole of 30 grams C2H6 = mass/molar mass

                                        = 30/30

                                       = 1 mole

  • Mole of 320 grams O2 = 320/32

                                       = 10 moles

Thus, C2H6 is the limiting reactant.

Mole ratio of C2H6 to CO2 according to the equation = 1:2

Since the mole of C2H6 is 1, the equivalent mole of CO2 would, therefore, be 2.

Mass of 2 moles CO2 = mole x molar mass

                                    = 2 x 44

                                      = 88 grams

More on stoichiometric calculations can be found here: brainly.com/question/8062886?referrer=searchResults

6 0
3 years ago
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