Answer:
Part a)

Part b)

Part c)
Since horizontal speed of truck and the arrow is same so the arrow will strike at the position of the archer as they both moving with same speed
Explanation:
Part a)
As we know that the arrow moves with uniform acceleration in vertical direction so we can use kinematics in Y direction
Here we know that

since the arrow lands at the same height so its vertical displacement of whole motion is zero
so we will have



Part b)
Horizontal distance moved by the arrow

here horizontal speed of arrow is same as that of speed of truck
so we will have


Part c)
Since horizontal speed of truck and the arrow is same so the arrow will strike at the position of the archer as they both moving with same speed
Answer:
Explanation:
An object is drop from a height, then it is in direction of gravity
g is +ve
When an object drop from a height, the initial velocity is 0,
U=0
Given that h=4.4×10^7m
V=?
g=9.81m/s^2
Then using equation of motion
V^2=U^2+2gh
V^2=0+2×9.81×4.4×10^7
V^2=86.33×10^7m/s
Take square root of both side
V=29381.63m/s
Now to km/s, divide by 1000
Since 1km=1000m
V=29.38km/s
Given:
f1 = 20 Hz
f2 = 20000 Hz
speed of sound at 20 degrees celcius = 343 m/s
Solution:
for f1 = 20 Hz,
Using the equation:
lambda = speed of sound / f1 = 343 / 20 = 17.15 m
For f2:
lambda = speed of sound / f2 = 343 / 20000 = 0.01775 m
Therefore the wavelength range of audible sound in air would be 17.15 m to 0.01775 m.
Answer:

Explanation:
From frequency of oscillation

Initially with the suspended string, the above equation is correct for the relation, hence

where k is force constant and m is the mass
When the spring is cut into half, by physics, the force constant will be doubled as they are inversely proportional

Employing f2/ f1, we have
