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nasty-shy [4]
3 years ago
14

It is desired to lay off certain horizontal distances for building layouts. The length of the tapes are not 100.00 ft. Determine

the field dimensions that should be used with the incorrect tape the lengths so that the correct dimensions are obtained. Desired dimension: 725.00 by 180.00 ft Incorrect tape length: 100.06 ft
Physics
1 answer:
Elodia [21]3 years ago
6 0

Answer:

725.44 by 180.11

Explanation:

If a 100-ft tape was used, the number of such tapes in 725 ft would be \dfrac{725}{100}=7.25

And in 180 ft would be \dfrac{180}{100}=1.8

The same number of tapes would be used for the incorrect tape to give the false dimension. This would be

100.06\times7.25 by 100.06\times1.8 =

725.44 by 180.11

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The density, or intensity, of a magnetic field is called flux.<br> True<br> False
aev [14]

Answer:

True :)

Explanation:

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3 years ago
Sound waves travel fastest through a A) gas. B) liquid. C) solid. D) vacuum.
earnstyle [38]

Sound waves travel faster through <em>solids</em> than they do through gases or liquids.  <em>(C)  </em>They don't travel through vacuum at all.

Example:

Speed of sound in normal air . . . around 340 m/s

Speed of sound in water . . . around 1,480 m/s

Speed of sound in iron . . . around 5,120 m/s

3 0
3 years ago
Read 2 more answers
A boy pulls a 28.0-kg box with a 230-N force at 35° above a horizontal surface. If the coefficient of kinetic friction between t
ddd [48]

Answer:

1977.696 J

Explanation:

Given;

Weight of the box = 28.0 kg

Force applied by the boy = 230 N

angle between the horizontal and the force = 35°

Therefore,

the horizontal component of the force = 230 × cosθ

= 230 × cos 35°

= 188.405 N

Coefficient of kinetic friction, μ = 0.24

Force by friction, f = μN

here,

N = Normal force = Mass × acceleration due to gravity

or

N = 28 × 9.81 = 274.68 N

therefore,

f = 0.24 × 274.68

or

f = 65.9232 N

Now,

work done by the boy, W₁ = 188.405 N × Displacement  

= 188.405 N × 30

= 5652.15 J

and,

the

work done by the friction, W₂ = - 65.9232 N × Displacement  

= - 65.9232 N × 30 m

= - 1977.696 J

[ since the friction force acts opposite to the direction of motion, therefore the workdone will be negative]

8 0
3 years ago
Two waves meet and overlap. The first wave has an amplitude of 4.6 centimeters and the second wave has an amplitude of 2 centime
vodka [1.7K]

Answer:

Explanation:

The amplitude of resultant wave as the result of  overlap of two waves depends upon the phase difference between the two.  If the waves meet crest to trough , the phase difference is 180 degree or they are in opposite phase . Hence they will destroy each other . The amplitude of resultant wave can be obtained by subtracting the amplitudes of two waves. They will interfere destructively.

Amplitude of resultant gives waves = 4.6 - 2 = 2.6 cm.

3 0
3 years ago
Which of the following are true statements? A. Like charges repel B. Unlike charges repel C. Unlike charges attract or D. Charge
Brums [2.3K]

Answer: The correct answers are (A) and (C).

Explanation:

The expression from electrostatic force is as follows;

F=\frac{kq_{1}q_{1}}{r^{2} }

Here, F is the electrostatic force, k is constant, r is the distance between the charges and q_{1},q_{1} are the charges.

The electrostatic force follows inverse square law. It is inversely proportional to the square of the distance between the charges. It is directly proportional to the product of the charges.

Like charges repel each other. There is a force of electrostatic repulsion between the like charges. Unlike charges attract each other. There is a force of electrostatic attraction between unlike charges.

The charges are induced on the neutral object when it is placed nearby the charged object without actually touching it.

Therefore, the true statements from the given options are as follows;

Like charges repel.

Unlike charges attract.

7 0
3 years ago
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