Angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.0466 rad/s.
Length of the cylinder, L = 9 mi
= (14.5mi)(1609.344 m / 1 mi)
= 23,335.48 m
Diameter of the cylinder, D = 4.78 mi
= (4.78 mi)(1609.344 m / 1 mi)
= 7692.645 m
Radius of the cylinder, r = D / 2
= ( 7692.645 m) / 2
= 3846.32 m
Centripetal acceleration is given by, ac = v^2 / r
We have the relation between linear velocity (v) and the angular velocity(ω) as
v = r ω
Then, ac = v2 / r
= (rω)2 / r
ac = ω^2 r
If the centripetal acceleration is equals the free fall acceleration of earth, then
ω^2 r = g
ω=0.0466 rad/s
- Angular acceleration is the term used to describe the rate of change in angular velocity. If the angular velocity is constant, the angular acceleration is constant.
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Answer:
The solid ball and hollow ball both will reach the bottom with the same speed.
Explanation:
The speed of the solid and hollow balls is independent of the mass and the radius. A solid and hollow ball experience same speed on a given incline.
The speed can be calculated as
v = √(10/7)gh
where g is gravitational acceleration and h is the height
sinθ = h/L
h = L*sinθ
h = 3*sin(35)
h = 1.72 m
v = √(10/7)*9.8*1.72
v = 4.91 m/s
Both balls will reach the bottom at the speed of 4.91 m/s.
Continental Tropical Air Mass. Your welcome matey
Answer:
ionic bonds formed from the electrostatic attraction between oppositely charged ions in a chemical compound.
Explanation:
