An object is dropped from rest from a height of 4.4 107 m above the surface of the Earth. If there is no air resistance, what is its speed when it strikes the Earth?
1 answer:
Answer:
Explanation:
An object is drop from a height, then it is in direction of gravity
g is +ve
When an object drop from a height, the initial velocity is 0,
U=0
Given that h=4.4×10^7m
V=?
g=9.81m/s^2
Then using equation of motion
V^2=U^2+2gh
V^2=0+2×9.81×4.4×10^7
V^2=86.33×10^7m/s
Take square root of both side
V=29381.63m/s
Now to km/s, divide by 1000
Since 1km=1000m
V=29.38km/s
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