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mylen [45]
3 years ago
6

Which element is less reactive, an element who's atoms have seven valence electrons or an Element whose atoms have eight valence

electrons? Explain.
Physics
1 answer:
hammer [34]3 years ago
6 0
<span>An element whose atoms have eight valence electrons each is much less reactive, because such an element already has the energy-minimizing electron configuration, a closed octet, that other elements achieve by reaction with one another. Elements with seven electrons in each valence shell have a strong drive to abstract another one from a less electronegative atom such as a metal.</span>
You might be interested in
Which statement best describes copper?
ira [324]

Answer:

D. It has a low resistance and allows charges to move freely.

Explanation:

The high conductivity of copper allow charges to move freely without the need of too much force. The conductivity decreases with increase in resistance. Low resistance also means less heating of the conductors. This property of copper makes it ideal for use in the manufacture of electric cables and conductors for various gadgets.

4 0
3 years ago
Two pans of a balance are 46.3 cm apart. The fulcrum of the balance has been shifted 0.633 away from the center by a dishonest s
soldier1979 [14.2K]

distance of each pan from the center or fulcrum is given as

r = 23.15 cm

now if dishonest shopkeeper shifted it by 0.633 cm from center

so distance on each side is given as

d_1 = 23.15 - 0.633 = 22.52 cm

d_2 = 23.15 + 0.633 = 23.78 cm

now the weight is balance as

W_1d_1 = W_2d_2

W(22.52) = W_2(23.78)

now we will have

W_2 = 0.95W

now we can find the percentage change as

percentage = \frac{W - W_2}{W} \times 100

percentage = 5%

5 0
3 years ago
Which of the following is not a velocity?*
ira [324]

Answer:

50 mph

Explanation:

doesn’t have direction

3 0
3 years ago
Read 2 more answers
Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic colli
serious [3.7K]

Answer:

pf = 198.8 kg*m/s

θ = 46.8º N of E.

Explanation:

  • Since total momentum is conserved, and momentum is a vector, the components of the momentum along two axes perpendicular each other must be conserved too.
  • If we call the positive x- axis to the W-E direction, and the positive y-axis to the S-N direction, we can write the following equation for the initial momentum along the x-axis:

       p_{ox} = p_{oAx} + p_{oBx}  (1)

  • We can do exactly the same for the initial momentum along the y-axis:

       p_{oy} = p_{oAy} + p_{oBy}  (2)

  • The final momentum along the x-axis, since the collision is inelastic and both objects stick together after the collision, can be written as follows:

       p_{fx} =  (m_{A} + m_{B} ) * v_{fx}  (3)

  • We can repeat the process for the y-axis, as follows:

       p_{fy} =  (m_{A} + m_{B} ) * v_{fy}  (4)

  • Since (1) is equal to (3), replacing for the givens, and since p₀Bₓ = 0, we can solve for vfₓ as follows:

       v_{fx} = \frac{p_{oAx}}{(m_{A}+ m_{B)}} = \frac{m_{A}*v_{oAx} }{(m_{A}+ m_{B)}} =\frac{17.0kg*8.00m/s}{46.0kg} =  2.96 m/s (5)

  • In the same way, we can find the component of the final momentum along the y-axis, as follows:

       v_{fy} = \frac{p_{oBy}}{(m_{A}+ m_{B)}} = \frac{m_{B}*v_{oBy} }{(m_{A}+ m_{B)}} =\frac{29.0kg*5.00m/s}{46.0kg} =  3.15 m/s (6)

  • With the values of vfx and vfy, we can find the magnitude of the final speed of the two-object system, applying the Pythagorean Theorem, as follows:

      v_{f} = \sqrt{v_{fx} ^{2} + v_{fy} ^{2}} = \sqrt{(2.96m/s)^{2} + (3.15m/s)^{2}} = 4.32 m/s (7)

  • The magnitude of the final total momentum is just the product of the combined mass of both objects times the magnitude of the final speed:

       p_{f} = (m_{A} + m_{B})* v_{f}  = 46 kg * 4.32 m/s = 198.8 kg*m/s (8)

  • Finally, the angle that the final momentum vector makes with the positive x-axis, is the same that the final velocity vector makes with it.
  • We can find this angle applying the definition of tangent of an angle, as follows:

       tg \theta = \frac{v_{fy}}{v_{fx}} = \frac{3.15 m/s}{2.96m/s} = 1.06 (9)

       ⇒ θ = tg⁻¹ (1.06) = 46.8º N of E

8 0
3 years ago
I need help fast!!!
Fantom [35]

You could easily help yourSELF if you simply follow the instructions in the question and "Use Ohm's law" to calculate the resistance.

Ohm's Law:  Resistance = (voltage) / (current)

Resistance = (10 v) / (5 A)

<em>Resistance = 2 ohms</em>

8 0
3 years ago
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