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1 year ago

If 0. 3 moles of H2O were produced, how many moles of carbon dioxide would also have been produced?

1 answer:

4 0

In a chemical reaction, 0. 3 moles of H2O result in the production of 0.2 moles of CO2. Chemical reactions are the means through which one group of chemical compounds are changed into another.

Chemical reactions are typically defined as changes that only affect the positions of electrons in the formation and breakage of chemical bonds between atoms, with no change to the nuclei (i.e., no change to the elements present). These types of changes are often included in the term chemical reactions.

Number of moles Definition We utilize this enormous quantity to measure atoms. Additionally, it equals the 6.022* 10 23 atoms that make up 12 grammes of carbon-12, or atoms.

C2H6 + 7/2O2 = 2CO2 + 3H2O,

where moles(CO2)=(2*0,3)/3=0.2 mol,

and n(CO2)=(2*0,3)/3=n(H2O);

n(CO2)=n(CO2)=n(H2O).

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3 years ago

10.0 mL of 3.0 M sulfuric acid has been added to 50.0 mL of water.

Cloud [144]

Answer:

the new concentration is 0.60M

Explanation:

The computation of the new concentration is shown below;

We know that

M1V1=M2V2

(3.0M) (10.0 mL) = M2 (50.0mL)

30 = M2 (50.0mL)

So, M2 = 0.60 M

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3 years ago

What is the molarity of solution obtained when 5.71 g of sodium carbonate-10-water is dissolved in water and made up to 250.0 cm

disa [49]

We have to know the molarity of solution obtained when 5.71 g of Na₂CO₃.10 H₂O is dissolved in water and made up to 250 cm³ solution.

The molarity of solution obtained when 5.71 g of sodium carbonate-10-water (Na₂CO₃.10 H₂O) is dissolved in water and made up to 250.0 cm^3 solutionis: (A) 0.08 mol dm⁻³

The molarit y of solution means the number of moles of solute present in one litre of solution. Here solute is Na₂CO₃.10 H₂O and solvent is water. Volume of solution is 250 cm³.

Molar mass of Na₂CO₃.10 H₂O is 286 grams which means mass of one mole of Na₂CO₃.10 H₂O is 286 grams.

5.71 grams of Na₂CO₃.10 H₂O is equal to $\frac{5.71}{286}$ = 0.0199 moles of Na₂CO₃.10 H₂O. So, 0.0199 moles of Na₂CO₃.10 H₂O present in 250 cm³ volume of solution.

Hence, number of moles of Na₂CO₃.10 H₂O present in one litre (equal to 1000 cm³) of solution is $\frac{0.0199 X 1000}{250}$ = 0.0796 moles. So, the molarity of the solution is 0.0796 mol/dm³ ≅ 0.08 mol/dm³

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3 years ago

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3 years ago

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