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meriva
3 years ago
11

Which value is equivalent to

Mathematics
1 answer:
Musya8 [376]3 years ago
4 0
It is a.) 64 over 49.
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Can someone clearly and correctly work out and show me how to answer QUESTION 19 AND 20??
Rudiy27
Is this a simultaneous equation question?
6 0
3 years ago
Let f(t) ANSWER: 1+ = t² - 1 t+3 Find f'(1)​
Luda [366]

Answer:

f(1) = 3

Step-by-step explanation:

f(t) = t² - 1t + 3

we want to find f(1)

all we have to do is replace the t's with 1 and evaluate

f(1) = (1)² - 1(1) + 3

evaluate exponent 1² = 1

f(1) = 1 - 1(1) + 3

multiply

f(1) = 1 - 1 + 3

subtract

f(1) = 3

4 0
2 years ago
What is the square root of 141?
serious [3.7K]
The square root of 141 = \sqrt{141}

This is because the two factors are 3 and 47, which both aren't perfect squares. You cannot take anything out.

If you want it simplified (like with a calculator) it would be:
\sqrt{141} =11.87
6 0
3 years ago
Read 2 more answers
Which of the following expressions could be used to estimate the difference between -12.34 and -4.8?
Sveta_85 [38]
-12+5

for -12.34,we take it as -12
for -4.8,we take it as -5

to measure the difference,here's what you need to do

-12-(-5)
=-12+5
thus the ans is -12+5

hope it helps
6 0
3 years ago
Read 2 more answers
Suppose that a recent poll of American households about car ownership found that for households with a car, 39% owned a sedan, 3
Dimas [21]

Let the total number of cars = 100

Total of sedan, van and sports cars = 39+33+7 = 79

Number of other cars = 100 - 79 = 21.

Let A be the event of owning a sedan,

B be the event of owning a van and

C be the event of owning a sports car.

D be the event of owning other cars.

Then, p(A) = \frac{39}{100}

p(B)=\frac{33}{100} and

p(C) = \frac{7}{100}

p(D) = \frac{21}{100}

Now,

p(non selection of van) = p(A ∪ C ∪ D)

= p(A) + p(C) + p(D)

=\frac{39}{100} +\frac{7}{100} +\frac{21}{100}

=\frac{67}{100}

= 0.67

The probability of none of the three selections would be a van is:

0.67 × 0.67 × 0.67

= 0.300763

=0.301

Hence, the correct option is (D).

6 0
3 years ago
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