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meriva
1 year ago
14

A pottery rectory kept track of the number of broken plates per shipment last week. Number of broken plates Number of shipments

376 2 380 . 6 567 737 5 928 2 964 3 X is the number of broken plates that a randomly chosen shipment had. What is the expected value of X? Write your answer as a decimal.
Mathematics
1 answer:
Paul [167]1 year ago
3 0

Therefore,

Expected value of X = 37.6 + 38 + 170.1 + 184.25 + 92.8 + 144.6

= 667.35

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Suppose $1750 is put into an account that pays an annual rate of 4.5%
Yanka [14]

Answer:

The amount in the account after six years is $2,288.98

Step-by-step explanation:

In this question, we are asked to calculate the amount that will be in an account that has a principal that is compounded quarterly.

To calculate this amount, we use the formula below

A = P(1+r/n)^nt

Where P is the amount deposited which is $1,750

r is the rate which is 4.5% = 4.5/100 = 0.045

t is the number of years which is 6 years

n is the number of times per year, the interest is compounded which is 4(quarterly means every 3 months)

we plug these values into the equation

A = 1750( 1 + 0.045/4)^(4 * 6)

A = 1750( 1 + 0.01125)^24

A = 1750( 1.01125)^24

A = 2,288.98

The amount in the account after 6 years is $2,288.98

6 0
3 years ago
Jason can make 7 origami cranes in 10 minutes. How many minutes will it take to make 1505 origami cranes
Angelina_Jolie [31]

Answer:

The unit rate = 7/10 cranes per minute

Step-by-step explanation:

So, the number of minutes would it would take Kenny to fold 1505 cranes is  

10/7 x 1505 = 2150 minutes

2150/60 = 35 5/6 hours

8 0
2 years ago
Read 2 more answers
X-y=3 slope intercept
LekaFEV [45]
Slope intercept is x=3, y=-3. Hope this helped!
8 0
3 years ago
Prove that <br><img src="https://tex.z-dn.net/?f=4cot45%20%5E%7B2%7D%20%20-%203tan%20%5E%7B2%7D%2060%20%2B%202sec%20%5E%7B2%7D60
sesenic [268]

Answer:

4 \cot {}^{2} (45)  - 3 \tan {}^{2} (60)  + 2 \sec {}^{2} (60)  = 3 \\

LHS = 4 \cot {}^{2} (45)  - 3 \tan {}^{2} (60)  + 2 \sec {}^{2} (60)  \\

let us first take a look at the values of the trigonometric ratios given in the question so that we get quite clear about what is to be done.

here ,

\cot(45)  = 1 \\  \\  \tan(60)  =  \sqrt{3}  \\  \\  \sec(60)  = 2

now ,

we just have to plug in the values considering certain other things given in the question and we're done!

so let's start ~

4(1) {}^{2}  - 3( \sqrt{3} ) {}^{2}  + 2(2) {}^{2}  \\ \\ \dashrightarrow \: 4(1) - 3(3) + 2(4) \\ \\ \dashrightarrow \: 4 - 9 + 8 \\\\ \dashrightarrow \: 12 - 9 \\ \\\dashrightarrow \: 3 = RHS

hence , proved ~

hope helpful :D

7 0
3 years ago
Distribute property -3(6+h)
ValentinkaMS [17]

Answer:

Answer: -18 + -3h

More simple: -18 - 3h

Step-by-step explanation:

  1. -3 × 6 = -18
  2. -3 × h = -3h
  3. Put them together: -18 + -3h
5 0
3 years ago
Read 2 more answers
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