Answer- 3x-56(x) =8
Explanation- Good luck
Answer:
a) 88% is a population characteristic.
Step-by-step explanation:
A population characteristic, also known as population parameter, describes a characteristic about the entire population of variables (usually numerically). Basically, it is a description (usually numerical) about a group of variables, obtained from the total population of such a variable.
WHILE
A statistic describes that same characteristic, only that it is obtained from a sample of variables taken from the population.
For the question above, a department notices that 88% of ALL their customers who use the store's credit plan pay their bills on time. It is evident that this is a population charasteristic, as it is obtained from examining the entire population of customers.
Hope this Helps!!!
Compute the differential for both sides:
4<em>y</em> - 3<em>xy</em> + 8<em>x</em> = 0
→ 4 d<em>y</em> - 3 (<em>y</em> d<em>x</em> + <em>x</em> d<em>y</em>) + 8 d<em>x</em> = 0
Solve for d<em>y</em> :
4 d<em>y</em> - 3<em>y</em> d<em>x</em> - 3<em>x</em> d<em>y</em> + 8 d<em>x</em> = 0
(4 - 3<em>x</em>) d<em>y</em> + (8 - 3<em>y</em>) d<em>x</em> = 0
When <em>x</em> = 0, we have
4<em>y</em> - 3•0<em>y</em> + 8•0 = 0 → 4<em>y</em> = 0 → <em>y</em> = 0
and with d<em>x</em> = 0.05, we get
(4 - 3•0) d<em>y</em> + (8 - 3•0) • 0.05 = 0
→ 4 d<em>y</em> + 0.4 = 0
→ 4 d<em>y</em> = -0.4
→ d<em>y</em> = -0.1
Answer:
P=0.125
If it is repeated 10,000, it is expected "3 tails in a row" about 1,250 times.
Step-by-step explanation:
When flipping a coin a number of times, we can modeled this as a random variable with a binomial distribution.
In this case, we have to calculate the probability of 3 consecutive tails. If we define p as the probability of getting a tail (which has a value of p=0.5 if it is an unbiased coin), the probability of getting 3 tails in a row is:
If that event of "flipping a coin 3 times" is repeated 10,000 times, we can expect to have 3 tails in a row about 1,250 times:
because we expect 0.125 events of this type for every try, so we can multiply this probability (or expected frequency) by the number of trials and we get the expected number of events described.
I would say that the answer is B
