Question

Triangle ABC has vertices A(–1, 0), B(4, 0), and C(2, 6). If ΔABC is translated using the function rule (x, y) → (x – 6, y – 5) and then rotated 180° clockwise, what would be the coordinates of the vertices of ΔA’’B’’C’’?
a. A’’(–5, 7), B’’(–5, 2), C’’(1, 4)
b. A’’(7, 5), B’’(2, 5), C’’(4, –1)
c. A’’(7, 5), B’’(2, 5), C’’(4, 1)
d. A’’(–7, –5), B’’(–2, –5), C’’(–4, 1)

Answer 1

Answer:

b.  A''(7, 5), B''(2, 5), C''(4, –1)

Step-by-step explanation:

Given vertices of ΔABC:

• A = (-1, 0)
• B = (4, 0)
• C = (2, 6)

Translation mapping rule:

(x, y) → (x – 6, y – 5)

Therefore:

• A' = (-1 - 6, 0 - 5) = (-7, -5)
• B' = (4 - 6, 0 - 5) = (-2, -5)
• C' = (2 - 6, 6 - 5) = (-4, 1)

Rotation of 180° clockwise rule:

(x, y) → (-x, -y)

Therefore:

• A'' = (-7, -5) = (7, 5)
• B'' = (-2, -5) = (2, 5)
• C'' = (-4, 1) = (4, -1)

Learn more about transformations here:

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