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iren [92.7K]
1 year ago
8

A wheel of radius 30.0 cm is rotating at a rate of 2.30 revolutions every 0.0810 s.Through what angle does the wheel rotate in 1

.00 s?What is the linear speed of a point on the wheel’s rim?What is the wheel’s frequency of rotation?
Physics
1 answer:
jeka57 [31]1 year ago
7 0

Given data

*The given radius of the wheel is r = 30.0 cm = 0.30 m

*Rate of rotation is 2.30 revolutions every 0.0810 s

The angle of the wheel rotates in one second is calculated as

\begin{gathered} \theta=(2.30\times2\pi)\times\frac{1}{0.0810} \\ =178.32\text{ radian} \end{gathered}

Hence, the angle of the wheel rotating in one second is 178.32 radian

The formula for the linear speed of a point on the wheel's rim is given as

v=r\omega

Substitute the known values in the above expression as

undefined

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Please answer the following question.
Dima020 [189]

The oceanic lithosphere is a layer on the Earth's crust that consists of rocks of the mantle.

<h3>What is the lithosphere?</h3>

The lithosphere can be defined as the outer rock layer present on the Earth's surface.

The oceanic lithosphere is composed of different rocks of the mantle such as, among others, gabbro and/or basalt.

The structure of the oceanic lithosphere is similar around the world because it is slender compared to the continental lithosphere and always determined by the supply of magma.

In conclusion, the oceanic lithosphere is a layer on the Earth's crust that consists of rocks of the mantle.

Learn more about the lithosphere here:

brainly.com/question/10508547

#SPJ1

6 0
2 years ago
By what factor will the Electrostatic Force between two charged objects change when the amount of charge on both objects doubles
Mademuasel [1]

Answer:

F' = (4/9)F

Explanation:

The electrostatic force between two charged objects is given by Coulomb's Law:

F = kq₁q₂/r²   -------------------- equation (1)

where,

F = Electrostatic Force

k = Coulomb's Constant

q₁ = magnitude of first charge

q₂ = magnitude of second charge

r = distance between charges

Now, when the charges and distance altered as follows:

q₁' = 2q₁

q₂' = 2q₂

r' = 3r

Then,

F' = kq₁'q₂'/r'²

F' = k(2q₁)(2q₂)/(3r)²

F' = (4/9)kq₁q₂/r²

using equation (1):

<u>F' = (4/9)F</u>

7 0
3 years ago
On a touchdown attempt, 95.00 kg running back runs toward the end zone at 3.750 m/s. A 113.0 kg line-backer moving at 5.380 m/s
dsp73

Answer:

(a) 1.21 m/s

(b) 2303.33 J, 152.27 J

Explanation:

m1 = 95 kg, u1 = - 3.750 m/s, m2 = 113 kg, u2 = 5.38 m/s

(a) Let their velocity after striking is v.

By use of conservation of momentum

Momentum before collision = momentum after collision

m1 x u1 + m2 x u2 = (m1 + m2) x v

- 95 x 3.75 + 113 x 5.38 = (95 + 113) x v

v = ( - 356.25 + 607.94) / 208 = 1.21 m /s

(b) Kinetic energy before collision = 1/2 m1 x u1^2 + 1/2 m2 x u2^2

                                               = 0.5 ( 95 x 3.750 x 3.750 + 113 x 5.38 x 5.38)

                                               = 0.5 (1335.94 + 3270.7) = 2303.33 J

Kinetic energy after collision = 1/2 (m1 + m2) v^2                

                                                = 0.5 (95 + 113) x 1.21 x 1.21 = 152.27 J

4 0
3 years ago
A piece of transparent material that is used to focus light and form a image
Soloha48 [4]

Convex Lenses are used to focus light and form a image. They are transparent.

They are one type of lenses. Different type of lenses are used to focus light differently. The basic lenses are concave and convex. Convex lenses converge light falling on it whereas concave lenses diverge light falling on it.

4 0
3 years ago
Read 2 more answers
During lightning strikes from a cloud to the ground, currents as high as 2.50×104 A can occur and last for about 40.0 μs . How m
Nezavi [6.7K]

Answer:

<h3>The charge transferred from the cloud to earth is 1 Coulomb.</h3>

Explanation:

Given :

Current I = 2.5 \times 10^{4} A

Time t = 40 \times 10^{-6} sec

We know that the current is the rate of flow of charge.

From the formula of current,

<h3>  I = \frac{Q}{t}</h3>

Where Q = charge transfer between cloud and earth.

 Q =I t

Q = 2.5 \times 10^{4} \times 40 \times 10^{-6}

Q = 1 C

Hence, the charge transferred from the cloud to earth is 1 Coulomb.

3 0
4 years ago
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