The temperature of the air in the open orang pipe has been altered by 18.73° C
The frequency of an open orang pipe is estimated by using the formula:
Then, the combination of the frequency of the tuning fork and the open orang pipe is:
These combinations of frequency produce 4 beats per sound.
i.e.
When it is altered, the beats first diminish and increase again by 4.
i.e.
If we equate both equations (1) and (2) together, we have:
However, from our previous knowledge, we understand that the velocity of an object varies directly proportional to the square root of its temperature.
Hence;
- when the temperature of the pipe = unknown ???
- the temperature of the open orang pipe = 15
∴
By squaring both sides, we have:
T = 306.726912 - 273
T ≅ 33.73 ° C
∴
The change in temperature ΔT = 33.73° C - 15° C
The change in temperature ΔT = 18.73° C
Learn more about wave frequency here:
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The answer would be letter choice B
Answer:
y = 9.64 m
Explanation:
This exercise should be solved using kinematics in one dimension, let's write the equations for the two cases presented
The rock is released
y = y₀ + V₀₁ t₁ - ½ g t₁²
In this case the speed starts is zero
y = y₀ - ½ g t₁²
The rock is thrown up
y = y₀ + v₀² t₂ -½ g t₂²
The height that reaches the floor is zero
y₀ - ½ g t₁² = y₀ + v₀₂ t₂ - ½ g t₂²
We use the initial velocity with the equation
v₂² = v₀₂² - 2 g y
At the point of maximum height v₂ = 0
v₀₂ = √ (2 g 
)
g (-t₁² + t₂²) = 2 √ (2 g ) t₂²
g (- 4.15² + 6.30²) = 2 √ (2 2 g) 6.3
g (22.4675) = 25.2 √ g
g² = 2²5.2 / 22.4675 g
g = 1.12 m / s²
Having the value of g we can use any equation to find the height
y = ½ g t₁²
y = ½ 1.12 4.15²
y = 9.64 m
The potential energy of a swing is greatest at the top of the swing. (Point A).
Both the effects (l<span>engthening of the transmitted signal's wavelength and decrease in its frequency) indicates that the object is moving away from the observer, and this phenomenon is called Doppler effect.
In fact, when the object is moving away from the observer, the relative distance between two consecutive crests of the wave emitted by the object increases to the observer eyes, since he's moving away. This means that the wavelength appears larger, and since the frequency is inversely proportional to the wavelength, the frequency appears smaller.</span>
