Answer:
I think its Pound or a gram
The stretching force acting on the second wire, given the data is 588 N
<h3>Data obtained from the question</h3>
- Radius of fist wire (r₁) = 3.9×10⁻³ m
- Force of first wire (F₁) = 450 N
- Radius of second wire (r₂) = 5.1×10⁻³ m
- Force of second wire (F₂) =?
<h3>How to determine the force of the second wire</h3>
F₁ / r₁ = F₂ / r₂
450 / 3.9×10⁻³ = F₂ / 5.1×10⁻³
cross multiply
3.9×10⁻³ × F₂ = 450 × 5.1×10⁻³
Divide both side by 3.9×10⁻³
F₂ = (450 × 5.1×10⁻³) / 3.9×10⁻³
F₂ = 588 N
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Answer:
V=34.2 m/s
Explanation:
Given that
Height , h= 54 m
Horizontal distance , x = 35 m
Given that , the ball is thrown horizontally , therefore the initial vertical velocity will be zero.
In vertical direction :
We know that
Now by putting the values in the above equation we got
Assume 
Thus
We also know that
In horizontal direction :
Thus the resultant velocity
V=34.2 m/s
Therefore the velocity will be 34.2 m/s.
Answer:
C sedimentary rocks is the answer.
Explanation:
Answer:
240 Ω
Explanation:
Resistance: This can be defined as the opposition to the flow of current in an electric field. The S.I unit of resistance is ohms (Ω).
The expression for resistance power and voltage is give as,
P = V²/R.......................... Equation 1
Where P = Power, V = Voltage, R = Resistance
Making R the subject of the equation,
R = V²/P.................... Equation 2
Given: V = 120 V, P = 60 W.
Substitute into equation 2
R = 120²/60
R = 240 Ω
Hence the resistance of the bulb = 240 Ω
