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3 years ago

13

Look at the picture below. The boy is swinging back and forth on the swing. At which point is the potential energy of a swing th

e greatest? swing Question 2 options: Point A (top) Point B (halfway down) Point C (bottom) Point D (halfway up)

2 answers:

Ilia_Sergeevich [38]3 years ago

5 0

The potential energy of a swing is greatest at the top of the swing. (Point A).

Eddi Din [679]3 years ago

4 0

The highest amount of potential energy is at the top because the kinetic energy is based on weight and mass at the highest point there is no speed, so that means there is no kinetic energy. In short, you answer is <span>Point A (top)

Hope this helps!</span>

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What is the electric force acting between two charges of -0.0050 C and

love history [14]

The electric force is $-3.6\cdot 10^8 N$ (attractive)

Explanation:

The magnitude of the electric force between two charges is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=9\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

In this problem, we have the following:

$q_1 = -0.0050 C$ (charge 1)

$q_2 = +0.0050 C$ (charge 2)

r = 0.025 m (distance)

Substituting, we find the electric force between the two charges:

$F=(9\cdot 10^9) \frac{(-0.0050)(0.0050)}{(0.025)^2}=-3.6\cdot 10^8 N$

And the negative sign means the force is attractive, since the two charges have opposite sign.

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

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3 years ago

Item 19 A student with arms outstretched stands on a platform that is rotating with a constant angular speed. The student then p

nadezda [96]

Answer:

An increase in angular speed due to conservation of energy priciple.

Explanation:

This leads to a decrease in your moment of inertia. This means that your angular velocity must increase as a result of conservation of energy principle and therefore you will spin faster.

It's also the same way this conservation of energy principle applies to ice skaters that makes them spin faster when they suddenly draw their arms inwards.

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3 years ago

How are Newton’s second and third laws of motion important to your everyday life?

Rasek [7]

Well, first off, Newtons second law of motion <span>deals with the motion of accelerating and decelerating objects.
W</span>e already know that from everyday life examples such as simply pushing a car that if 2 people push a car on a flat road it will accelerate faster than if one person was pushing it... Therefore, there is a relationship between the size of the force and the acceleration.
Now onto the third law of motion. First of all, what is the third law of motion? Well, a force is a push or a pull that acts upon an object as a results of its interaction with another object. Forces result from interactions! According to Newtons third law, whenever one object, and another object interact with each other, they exert forces upon each other. "For every action, there is an equal and opposite reaction." The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. So, how is this important to everyday life you may ask?
<span>Well, the action-reaction force pairs are found everywhere in your body.
For example, right now as I am typing, my tendons are exerting forces on bones, and those bones exert reaction forces on the tendons, as muscles contract, pulling my fingers on the keys. I press on those keys, and they press back on my fingers. See? Since i'm pressing on the keys, the press back on me. Its opposite from each other, as stated in the quite above. "</span><span>For every action, there is an equal and opposite reaction." </span>

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4 years ago

The space shuttle is located exactly half way between the earth and the moon. Which statement is true regarding the gravitationa

sdas [7]

Answer:

The correct answer is option B)

Explanation:

Considering the given question as -

The space shuttle is located exactly half way between the earth and the moon. Which statement is true regarding the gravitational pull on the shuttle? A) The moon pulls more on the shuttle. B) The earth pulls more on the shuttle. C) Both are equal due to equal distances. D) Both are equal due to the mass of the shuttle.

We know that gravitational pull (F) between any two bodies of mass $M_{1}$ and $M_{2}$ is given by -

F = $\dfrac{GM_{1}M_{2} }{r^{2} }$ where 'r' is the distance between the two bodies.

Let ,

$M_{e}$ : Mass of the earth

$M_{m}$ : Mass of the moon

m : Mass of the satellite

$r_{e}$ : Distance of satellite from earth

$r_{m}$ : Distance of satellite from moon

Given that $r_{e}$ = $r_{m}$

Let $r_{e}$ = $r_{m}$ =r

Force on satellite by the earth is -

$F_{e}$ = $\dfrac{GM_{e}m }{r^{2} }$

Force on satellite by the moon is -

$F_{m}$ = $\dfrac{GM_{m}m }{r^{2} }$

∵ Mass of earth ( $M_{e}$ ) > Mass of moon ( $M_{m}$ )

∴ $F_{e}$ > $F_{m}$

∴ The gravitational pull of earth on satellite is more than that of the moon.

4 0

4 years ago

A daredevil is shot out of a cannon at 31.4 ◦ to the horizontal with an initial speed of 25.9 m/s. A net is positioned a horizon

Tanzania [10]

Answer:

The net should be placed at a height of 8.45 m

Explanation:

In order to calculate the height you have to apply the equations of <em>projectil motion.</em>

For x-axis, the position at a time t is given by:

Xf=Xo +(VoCosα)t (I)

Where Xf is the final position, Xo is the initial position, Vo is the initial speed and t is the time.

For the y-axis, the position at a time t is given by:

Yf=Yo + (VoSinα)t - 0.5g $t^{2}$ (II)

Where Yf is the final position, Yo is the initial position, Vo is the initial speed, t is the time and g is the acceleration of gravity.

For both equations, ∝ is the angle formed by the cannon and the horizontal

The height where the net should be placed in order to catch the daredevil is given by replacing the time when the daredevil will be in the horizontal position of 39.7 m in the equation of position for the y-axis.

So, you have to calculate the time using (I)

Let the system of reference be placed at x=o and y=o

Xf= 0 + 25.9Cos(31,4◦)t

Xf=39.7

39.7=22.1t

Dividing both sides by 22.1 to find the value of t:

t=1.79 seconds

Replacing the time in equation (II) to find the height:

Yf=0 +25.9Sin(31,4◦)(1.79) - 0.5(9.8) $1.79^{2}$

Yf= 8.45 m

So the height is 8.45 m

4 0

4 years ago