Question

Write an equation for the parabola who’s vertex is at (3,6) and which passes through (4,4)

Answer 1

Problem

Solution

For this case we know that the vertex is given by (3,6) and the genera equation for a parabola is given by:

y= a(x-h)^2 +k

Where h = 3, k=6 and replacing we have:

y= a(x-3)^2 +6

And we can find the value of a with the point given x= 4, y=4

4= a(4-3)^2 +6

4= a +6

a= 4-6=-2

And the correct equation would be:

d. y= -2(x-3)^2 +6