The Expression for the Area a of the rectangle as a function of length L is given by A(L) = 12L - L^2 .
Let,
length, L, and the width, W, are components that help determine the area, A, and the perimeter, P of the rectangle. These are given by the following equations
A=LW
P=2L+2W
Given,
Perimeter of the Rectangle = 24m.
We are asked to express the perimeter of the rectangle as a function of the length, L, of one of its sides.
We will first set up the equation of the Perimeter of the rectangle. We can let the width of the rectangle be W.
P = 2L+2W
24 = 2L+2W
12 = L+W
W = 12-L
Since we want to express the Area as a function of L, we have to find the value of W in terms of L. This is so we can eliminate the width in the equation for the Area. The Area as a function of L is as follows.
A(L, W) = LW
A(L) = L(12-L)
A(L) = 12L-L^2
Therefore, the Area as a function of L is given by A(L) = 12L-L^2.
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Answer:

Step-by-step explanation:
The given rational function is

Let us expand the numerator to get;


We can observe that, the degree of the numerator is the same as the degree of the denominator.
Therefore the horizontal asymptote is the ratio of the coefficient of the leading terms:

The horizontal asymptote is

Answer:
Correct option: B. About 1,686.
Step-by-step explanation:
The formula to compute the order quantity (Q) is:

Here

Compute the order quantity as follows:

Thus, the order quantity was about 1,686.
64, because its square root is 8.
49, because its square root is 7.
144, because its square root is 12.
4, because its square root is 2.