2 years ago

Beta radiation requires _____ to be stopped.Question 17 options:paperglassaluminumlead

Physics

1 answer:

Ratling [72]2 years ago

5 0

Beta decay or radiation produces electrons or positrons depending on the decay modes which are

$\begin{gathered} \beta^-(electron_{}\text{ emission)} \\ \beta^+(positron_{}\text{ emission)} \end{gathered}$

The Beta radiation can be stopped by an aluminium.

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After a new aircraft has passed ground and flight tests, the aircraft must receive a series of certificates before it can be mas

ollegr [7]

Answer:

A production certificate Shows that the aircraft met FAA construction and performance standards

Explanation:

Federal Airport Authority (FAA), is the body that check the standard operations of air craft activities in a country.

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4 years ago

A basketball player jumped straight up to grab a rebound. If she was in the air for 0.80 second, how high did she jump?

Kazeer [188]

-- She went up for 0.4 sec and down for 0.4 sec.

-- The vertical distance traveled in gravity during ' t ' seconds is

   D = (1/2) x (g) x (t)²

   = (1/2) (9.8 m/s²) (0.4 sec)²

   = (4.9 m/s²) x (0.16 s²)

   = 0.784 meter ( B )

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3 years ago

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The figure below shows an acceleration-versus-force graph for three objects pulled by rubber bands. The mass of object 2 is 0.20

lawyer [7]

Such a great question
answer:
object 1 = 0.1kg
object 2 = 0.5kg

if you can read this

4 0

3 years ago

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MARKING BRAINLIEST! The velocity of sound waves in air is 343 m/s, 1,007 m/s in helium and 267 m/s in carbon dioxide. Which one

FromTheMoon [43]

Answer:

In helium

Explanation:

Since the units are the same, the value should only be considered.

6 0

3 years ago

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A 22-g bullet traveling 240 m/s penetrates a 2.0-kg block of wood and emerges going 150 m/s. If the block is stationary on a fri

sveta [45]

Answer:

After the bullet emerges the block moves at 0.99 m/s

Explanation:

Given;

mass of bullet, m₁ = 22 g = 0.022 kg

initial speed of the bullet, u₁ = 240 m/s

final speed of the bullet, v₁ = 150 m/s

mass of block, m₂ = 2.0 kg

initial speed of the block, u₂ = 0

Let the final speed of the block = v₂

Apply principles of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

0.022 x 240 + 2 x 0 = 0.022 x 150 + 2v₂

5.28 = 3.3 + 2v₂

5.28 - 3.3 = 2v₂

1.98 = 2v₂

v₂ = 1.98 / 2

v₂ = 0.99 m/s

Therefore, after the bullet emerges the block moves at 0.99 m/s

3 0

4 years ago