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ikadub [295]
3 years ago
14

MARKING BRAINLIEST! The velocity of sound waves in air is 343 m/s, 1,007 m/s in helium and 267 m/s in carbon dioxide. Which one

is the fastest?
Physics
2 answers:
Juli2301 [7.4K]3 years ago
7 0

Answer:

(helium) - will be your answer.

FromTheMoon [43]3 years ago
6 0

Answer:

In helium

Explanation:

Since the units are the same, the value should only be considered.

You might be interested in
How do cells maintain homeostasis
Vikki [24]

Answer:

because they become home for them when they are in there for such a along time

5 0
4 years ago
: The truck is to be towed using two ropes. Determine the magnitudes of forces FA and FB acting on each rope in order to develop
Sholpan [36]

Answer:

Fa=774 N

Fb=346 N

Explanation:

We will solve this problem by equating forces on each axis.

  1. On x-axis let forces in positive x-direction be positive and forces in negative x-direction be negative
  2. On y-axis let forces in positive y-direction be positive and forces in negative y-direction be negative

While towing we know that car is mot moving in y-direction so net force in y-axis must be zero

⇒∑Fy=0

⇒Fa*sin(50)-Fb*sin(20)=0

⇒Fa*sin(50)=Fb*sin(20)

⇒Fa=2.24Fb

Given that resultant force on car is 950N in positive x-direction

⇒∑Fx=950  

⇒Fa*cos(20)+Fb*cos(50)=950

⇒2.24*Fb*cos(20)+Fb(50)=950

⇒Fb*(2.24*cos(20)+cos(50))=950

⇒Fb=\frac{950}{2.24*cos(20)+cos(50)}

⇒Fb=\frac{950}{2.24*0.94+0.64}

⇒ Fb=\frac{950}{2.75}=345.5

⇒Fa=2.24*Fb

      =2.24*345.5

      =773.93

Therefore approximately, Fa=774 N and Fb=346 N

5 0
3 years ago
A man takes 20 seconds to climb 5m up a ladder. He weighs 720N. Calculate the power he must deliver to do this.
Inessa05 [86]

Answer:

180 W

Explanation:

The work done by the man against gravity is equal to its gain in gravitational potential energy:

W=mg\Delta h

where

(mg) = 720 N is the weight of the man

\Delta h= 5 m is the change in height

Substituting,

W=(720)(5)=3600 J

The power he must deliver is given by

P=\frac{W}{t}

where

W = 3600 J

t = 20 s is the time taken

Substituting,

P=\frac{3600}{20}=180 W

3 0
4 years ago
You are observing the radiation from a distant active galaxy and you notice that the amplitude of the signal varies in strength
GREYUIT [131]

Answer:

Period of the signal.

Explanation:

So, this question is all about a concept in physics or astronomy which is called or known as Radiation Astronomy and Galactic Nuclei that are active. This concept talks most about Quasars; a powerful radiating object which derives its power from black holes.

When You take a look at Quasars, we get the to know that the more you think you can see, the more they move away from us.

Thus, when "You are observing the radiation from a distant active galaxy and you notice that the amplitude of the signal varies in strength regularly over a certain period. The maximum possible size for the source of this radiation can now be calculated from the "PERIOD OF THE SIGNAL.

NB: not the amplitude but the period.

7 0
4 years ago
About light and energy
Sophie [7]
E = MC^2. Albert Einstein's proven formula. When mass travels at the square of speed of light, the mass gets converted into energy
7 0
3 years ago
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