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Hitman42 [59]
1 year ago
14

Technician A ay that acid rain doe the mot harm when it firt fall on a finih. Technician B ay that hard water potting i uually j

ut a urface problem that can be wahed off. Who i right?
Engineering
1 answer:
Tamiku [17]1 year ago
6 0

Technician B is right say that hard water potting i usually jut a Surface problem that can be wahed off.

What do you mean by Hard water?

The amount of dissolved calcium and magnesium in the water determines its hardness. Calcium and magnesium are the main dissolved minerals in hard water. The last time you washed your hands, you might have actually felt the effects of hard water.

What do you mean by acid rain?

Any type of precipitation that contains acidic elements, such as sulfuric or nitric acid, that falls to the ground from the atmosphere in wet or dry forms is referred to as acid rain, also known as acid deposition. Rain, snow, fog, hail, and even acidic dust can fall under this category.

Some plants are sensitive to excessive moisture around their root zone, so it may be necessary to increase drainage when growing plants in pots. Additionally, standing water at the bottom of the pot can cause root rot.

Many university agriculture extension agencies have thoroughly debunked the old garden myth that adding rocks to the bottom of a pot will increase drainage.

Learn more about hard water click here:

brainly.com/question/28178305

#SPJ4

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For a certain gas, Cp = 840.4 J/kg-K; and Cv = 651.5 J/kg-K. How fast will sound travel in this gas if it is at an adiabatic sta
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Answer:

The speed of the sound for the adiabatic gas is 313 m/s

Explanation:

For adiabatic state gas, the speed of the sound c is calculated by the following expression:

c=\sqrt(\gamma*R*T)

Where R is the gas's particular constant defined in terms of Cp and Cv:

R=Cp-Cv

For particular values given:

R=840.4 \frac{J}{Kg-K}- 651.5 \frac{J}{Kg-K}

R=188.9 \frac{J}{Kg-K}

The gamma undimensional constant is also expressed as a function of Cv and Cp:

\gamma=Cp/Cv

\gamma=840.4 \frac{J}{Kg-K} / 651.5 \frac{J}{Kg-K}

\gamma=1.29

And the variable T is the temperature in Kelvin. Thus for the known temperature:

c=\sqrt(1.29*188.9 \frac{J}{Kg-K}*377 K)

c=\sqrt(91867.73 \frac{J}{Kg})

The Jules unit can expressing by:

J=N.m=\frac{Kg.m}{s^2}* m

J=\frac{Kg.m^2}{s^2}

Replacing the new units for the speed of the sound:

c=\sqrt(91867.73 \frac{Kg.m^2}{Kg.s^2})

c=\sqrt(91867.73 \frac{m^2}{s^2})

c=313 m/s

3 0
3 years ago
Read 2 more answers
Three capillary tubes with different radius (r1=1.0mm, r2=0.1mm, r3=0.01mm) are inserted into the same cup of water. The surface
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Explanation:

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4 0
3 years ago
Direction: List down or enumerate the type of outlets you want to install on your dream house. Also indicate the quantity (in pi
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6 0
2 years ago
An aircraft component is fabricated from an aluminum alloy that has a plane strain fracture toughness of 40MPa. It has been dete
Nataly [62]

Answer:

Yes, fracture will occur

Explanation:

Half length of internal crack will be 4mm/2=2mm=0.002m

To find the dimensionless parameter, we use critical stress crack propagation equation

\sigma_c=\frac {K}{Y \sqrt {a\pi}} and making Y the subject

Y=\frac {K}{\sigma_c \sqrt {a\pi}}

Where Y is the dimensionless parameter, a is half length of crack, K is plane strain fracture toughness, \sigma_c  is critical stress required for initiating crack propagation. Substituting the figures given in question we obtain

Y=\frac {K}{\sigma_c \sqrt {a\pi}}= \frac {40}{300\sqrt {(0.002*\pi)}}=1.682

When the maximum internal crack length is 6mm, half the length of internal crack is 6mm/2=3mm=0.003m

\sigma_c=\frac {K}{Y \sqrt {a\pi}}  and making K the subject

K=\sigma_c Y \sqrt {a\pi}  and substituting 260 MPa for \sigma_c  while a is taken as 0.003m and Y is already known

K=260*1.682*\sqrt {0.003*\pi}=42.455 Mpa

Therefore, fracture toughness at critical stress when maximum internal crack is 6mm is 42.455 Mpa and since it’s greater than 40 Mpa, fracture occurs to the material

6 0
3 years ago
When you multiply monomials with the same variables, you multiply the coefficients and add the exponents!
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Answer: ok

Explanation:

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