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Alecsey [184]
3 years ago
12

Much of the workd went to bed hungry

Engineering
1 answer:
Marysya12 [62]3 years ago
7 0
The workers went to bed hungry probably because they are hard workers and so didn’t want to eat because they didn’t want to take break┌(; ̄◇ ̄)┘
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Why might construction crews want to install pipes before the foundation is poured
Crazy boy [7]

The answer is choice C

Explanation:

As during construction ,the site is cleared for all debris before laying out the foundation. Even the sewer lines are dug out .

So it will be useful for the construction crews to  connect the pipes to the sewer lines before the foundation is poured.

But usually the steps take in construction activity is:- first the site is cleared for the foundation to be poured  and once the foundation wall is set , then all utilities , including plumbing and electrical activities are done.,

After this process is over, the city inspector comes to check whether the foundation has been laid down as per the code of construction.

Only after that the rest of the construction activity follows through.

3 0
3 years ago
What is thermodynamics system? Briefly explain (i) control mass system (ii) control volume system. Comment briefly on control ma
olga2289 [7]

Explanation:

Thermodynamics system :

 Thermodynamics system is a region or space in which study of matters can be done.The system is separated from surroundings by a boundary this boundary maybe flexible or fixed it depends on situations.The out side the system is called surroundings.

Generally thermodynamics systems are of three types

1.Closed system(control mass system)

  Only energy transfer take place ,no mass transfer take place.

2.Open system(control volume system)

 Both mass as well as energy transfer take place.

3.Isolated system

   Neither mass or nor energy transfer take place.

At steady state ,property is did not changes with respect to time.

3 0
3 years ago
Discuss the environmental concerns regarding microfibre products
zlopas [31]

I don't know

Explanation:

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8 0
3 years ago
Calculate the mean and median of the following
AfilCa [17]

Answer:

mean:24/5

ascending order:1,2,3,4,5,5,6,6,7,9

median:5

8 0
3 years ago
A cylindrical specimen of some metal alloy having an elastic modulus of 108 GPa and an original cross-sectional diameter of 4.5
IgorC [24]

Answer:

The maximum length of the specimen before the deformation was 358 mm or 0.358 m.

Explanation:

The specific deformation ε for the material is:

\epsilon = \deltaL /L (1)

Where δL and L represent the elongation and initial length respectively. From the HOOK's law we also now that for a linear deformation, the deformation and the normal stress applied relation can be written as:

\sigma = E/ \epsilon (2)

Where E represents the elasticity modulus. By combining equations (1) and (2) in the following form:

L= \delta L/ \epsilon

\epsilon =\sigma /E  

So by calculating ε then will be possible to find L. The normal stress σ is computing with the applied force F and the cross-sectional area A:

\sigma=F/A

\sigma=\frac{F} {\pi*d^2/4}

\sigma=\frac{2170 N}{\pi*4.5 mm^2/4}

\sigma= 136000000 Pa= 136 Mpa  

Then de specific defotmation:

\epsilon =136 MPa / 108 GPa = 1.26*10^{-3}

Finally the maximum specimen lenght for a elongation 0f 0.45 mm is:

L= 0.45 mm/ 1.26*10^{-3} = 358 mm = 0.358 m

4 0
3 years ago
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