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n200080 [17]
3 years ago
6

He is going ___ in the hot air ballon​

Engineering
1 answer:
Vladimir [108]3 years ago
5 0

no artical shoul be used here

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why did my dirtbike just stop when i was riding it, and now when i start it it sounds like it has a knock, and wont stay running
chubhunter [2.5K]

Answer: check the engines i swear if ur talking about an actual bike im gonna be so embarrassed lma0

7 0
3 years ago
Read 2 more answers
3
liq [111]

Answer:

a

Explanation:

3 0
3 years ago
A particle travels along a straight line with a velocity v = (12 – 3t2) m/s. When t = 1 s, the particle is located 10 m to the l
arlik [135]

Answer:

The displacement from t = 0 to t = 10 s,  is -880 m

Distance is 912 m

Explanation:

v = (12 - 3t^2) m/s = ds/dt.  .  . . . . . . . .  A

integrate above equation we get

s = 12t - t^3 + C

from information given in the question  we have

t = 1 s, s = -10 m

so distance s will be

-10 = 12 - 1 + C,

C = -21

s(t) = 12t - t^3 - 21

we know that acceleration is given as

a(t) = dv/dt = -6t  

[FROM EQUATION A]

Acceleration at  t = 4 s, a(4) = -24 m/s^2

for the displacement from t = 0 to t = 10 s,

s(10) - s(0) = (12*10 - 10^3 - 21) - (-21) = -880 m

the distance the particle travels during this time period:

let v = 0,

3t^2 = 12

t = 2 s

Distance = [s(2) - s(0)] + [s(2) - s(10)] = [1\times 2 - 2^3] + [(12\times 2 - 2^3) - (12\times 10 - 10^3)] = 912 m

7 0
4 years ago
a cantilever beam 1.5m long has a square box cross section with the outer width and height being 100mm and a wall thickness of 8
djverab [1.8K]

Answer:

a) 159.07 MPa

b) 10.45 MPa

c) 79.535 MPa

Explanation:

Given data :

length of cantilever beam = 1.5m

outer width and height = 100 mm

wall thickness = 8mm

uniform load carried by beam  along entire length= 6.5 kN/m

concentrated force at free end = 4kN

first we  determine these values :

Mmax = ( 6.5 *(1.5) * (1.5/2) + 4 * 1.5 ) = 13312.5 N.m

Vmax = ( 6.5 * (1.5) + 4 ) = 13750 N

A) determine max bending stress

б = \frac{MC}{I}  =  \frac{13312.5 ( 0.112)}{1/12(0.1^4-0.084^4)}  =  159.07 MPa

B) Determine max transverse shear stress

attached below

   ζ = 10.45 MPa

C) Determine max shear stress in the beam

This occurs at the top of the beam or at the centroidal axis

hence max stress in the beam =  159.07 / 2 = 79.535 MPa  

attached below is the remaining solution

6 0
3 years ago
O que é necessário se conhecer para a determinação de uma força concentrada em um ponto?
skelet666 [1.2K]

Answer: its c

Explanation:

7 0
3 years ago
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