2 years ago

He is going ___ in the hot air ballon

Engineering

1 answer:

Vladimir [108]2 years ago

5 0

no artical shoul be used here

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Studentka2010 [4]

Answer:

Net discharge per hour will be 3.5325 $m^3/hr$

Explanation:

We have given internal diameter d = 25 mm

Time = 1 hour = 3600 sec

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We know that area is given by

$A=\pi r^2=3.14\times (12.5\times 10^{-3})^2=490.625\times 10^{-6}m^2$

We know that discharge is given by $Q=AV$ , here A is area and V is velocity

So $Q=AV=490.625\times 10^{-6}\times 2=981.25\times 10^{-6}m^3/sec$

So net discharge in 1 hour = $981.25\times 10^{-6}m^3/sec\times 3600=3.5325m^3/hour$

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3 years ago

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A bona fide occupational qualification defense

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Do not mix Antifreeze with used oil

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He is going ___ in the hot air ballon​

He is going ___ in the hot air ballon