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Solnce55 [7]
3 years ago
6

Answer the following either true (T) or false (F) (5 pts)

Engineering
1 answer:
likoan [24]3 years ago
6 0

Answer:

1. True

2. True

3. False

Explanation:

The office location is where the soil layer is not uniform. The thickness of the soil varies which could lead to doors being jammed. The engineer needs to estimate the differential in clay soil.

The inclined surface can hold less weight than a vertical surface. The capacity to hold the weight is due to the gravitational force which is exerted to the load.

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Which of the following is most useful for doing research?
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Answer:

Web Browser

Explanation:

Because you dont use a messaging app or presentation software to look up stuff its common knowledge

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Light duty scaffolds are to be used for loads up to 25 lbs./sq. ft.<br> True<br> False
11Alexandr11 [23.1K]

Answer:

The answer is true

Explanation:

Light duty scaffolds are to be used for loads up to 25 lbs./sq. ft.

6 0
2 years ago
A 12 m thick layer of Chicago clay is doubly drained. This means that a very previous layer compared to the clay exists on top o
iren2701 [21]

Answer:

At 3 =99.60

At 6 =66.66

At 12 =33.38

Please see attachment for the percent consolidation.

3 0
3 years ago
Where would a salamander most likely be found?<br> A salamander would most likely be found in
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Salamanders live in or near water, or find shelter on moist ground and are typically found in brooks, creeks, ponds, and other moist locations
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3 years ago
Read 2 more answers
End A of the uniform 5-kg bar is pinned freely to the collar, which has an acceleration = 4 m/s2 along the fixed horizontal shaf
sergiy2304 [10]

Answer:

Fa = 57.32 N

Explanation:

given data

mass = 5 kg

acceleration = 4 m/s²

angular velocity ω = 2 rad/s

solution

first we take here moment about point A that is

∑Ma = Iα +  ∑Mad    ...............1

put here value and we get

so here I = ( \frac{1}{12} ) × m × L²    ................2

I = ( \frac{1}{12} ) × 5 × 0.8²

I = 0.267 kg-m²  

and

a  is =  r × α    

a  = 0.4 α

so now put here value in equation is 1

0 = 0.267 α + m r α (0.4) - m A (0.4)

0 = 0.267 α + 5 (0.4α) (0.4 ) - 5 (4) 0.4

so angular acceleration α = 7.5 rad/s²

so here force acting on x axis will be

∑ F(x) = m a(x)    ..............3

a(x) = m a - m rα

put here value

a(x) = 5 × 4 -  5 × 0.4 × 7.5

a(x) = 5 N

and

force acting on y axis will be

∑ F(y) = m a(y)    .............. 4

a(y) - mg = mrω²

a(y) - 5 × 9.81  = 5 × 0.4 × 2²

a(y) = 57.1 N

so

total force at A will be

Fa = \sqrt{a(x)^2+a(y)^2}    ...............5

Fa = \sqrt{(57.1)^2+(5)^2}  

Fa = 57.32 N

3 0
3 years ago
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