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3 years ago

10

Whenever you are around construction sites, you should A speed up so you get through it quicker and avoid falling rocks B maneuv

er so that you aren’t caught behind a slower moving vehicle C shift to neutral D slow down

1 answer:

erastovalidia [21]3 years ago

3 0

Answer:

D

Explanation:

You don't want to crash into a construction vehicle.

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A transformer has 300,000 windings in its primary coil and uses 12,000V AC input. (4 points) How many windings would be needed t

viva [34]

Answer:

2750

Explanation:

The number of windings and the voltage are proportional.

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Let n represent the number of windings to produce 110 Vac. Then the proportion is ...

n/110 = 300,000/12,000

n = 110(300/12) = 2750 . . . . multiply by 110

2750 windings would be needed to produce 110 Vac at the output.

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2 years ago

A First Stage in a turbine receives steam at 10 MPa, 800 C with an exit pressure of 800 KPa. Assume the stage is adiabatic and r

9966 [12]

Answer

given,

P₁ = 10 MPa T₁ = 800

P₂ = 800 KPa T₂ = ?

Using formula

$\dfrac{T_2}{T_1} = (\dfrac{P_2}{P_1})^{\dfrac{n-1}{n}}$

For steam n = 1.33

$\dfrac{T_2}{800+273} = (\dfrac{800\times 10^{3}}{10\times 10^{6}})^{\dfrac{1.33-1}{1.33}}$

T₂ = 573.368 K

T₂ = 573.368 - 273 = 300.368 °C

$W = \dfrac{P_1V_1-P_2V_2}{n-1}$

= $\dfrac{mR(T_1-T_2)}{n-1}$

= $\dfrac{1\times 0.287\times (800 - 300.368)}{1.33-1}$

W = 434.53 kJ/kg

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3 years ago

Consider three branch prediction schemes: predict not taken, predict taken, and dynamic prediction. Assume that they all have ze

SOVA2 [1]

Answer:

Check the explanation

Explanation:

1. When a branch is taken with 5% frequency, the branch prediction scheme is "predict taken" because the process has to begin fetching and then execute at the target address.

2. When a branch is taken with 95% frequency, the branch prediction scheme is "predict not taken" because the branch outcome is definitely known.

3. When a branch is taken with 70% frequency, the prediction scheme is "dynamic prediction" the branch prediction can dynamically change during the program execution.

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4 years ago

Which of the following is NOT a common problem or mistake with blueprints?

Nikitich [7]

Answer:

illegible.writng

Explanation:

am I right

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3 years ago

A) If a given directional antenna can receive 15 times the power of an isotropic antenna, what is

Sauron [17]

The gain of the directional antenna is calculated based on the comparison

with an hypothetical isotropic antenna.

a) The gain in dBi of the isotropic antenna is approximately <u>11.76 dBi</u>

b) The power received by the isotropic antenna is approximately <u>0.61 mW</u>

Reasons:

a) The number of times the power of the directional antenna is stronger than the isotropic antenna, G = 15 times

The gain in dBi is given as follows;

$\displaystyle G = \mathbf{10^{\dfrac{G(dBi)}{10} }}$

Which gives;

$\displaystyle 15 = 10^{\dfrac{G(dBi)}{10} }$

$\displaystyle \dfrac{G(dBi)}{10} = \frac{ln(15)}{ln(10)}$

$\displaystyle G(dBi)} = 10 \times \frac{ln(15)}{ln(10)} \approx 11.76$

The power gain of the isotropic antenna, G(dBi) ≈ <u>11.76 dBi</u>

b) When the gain of the directional antenna is 2.15 dBi and it received 1 mW of power, we have;

The number of times stronger the directional antenna is, is found as follows;

$\displaystyle G = 10^{\dfrac{2.15}{10} } \approx \mathbf{1.64}$

The 2.15 dBi directional antenna receives the signal approximately 1.64 times stronger than the isotropic antenna, therefore;

$\displaystyle The \ power \ received \ by \ the \ isotropic \ antenna = \frac{1 \, mW}{1.64} \approx \underline {0.61 \, mW}$

Learn more here:

brainly.com/question/17587029

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3 years ago