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Snezhnost [94]
1 year ago
6

I need help I’ve been having trouble with this chapter for about a week

Mathematics
1 answer:
Harman [31]1 year ago
5 0

Given:

3x^2+20x+33

Find-:

Factorization of the equation.

Sol:

A simple method of factorization is to multiply in first and last order then break it down into parts to make the middle number then.

\begin{gathered} =3\times33 \\ =99 \end{gathered}

The factor of 99 is:

So take factor :

\begin{gathered} 11\text{ and \lparen3}\times3) \\  \\ 11\text{ and  9} \end{gathered}

Factorization of the equation is:

\begin{gathered} =3x^2+20x+33 \\  \\ =3x^2+11x+9x+33 \end{gathered}

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Determine the truth value of each of these statements if thedomainofeachvariableconsistsofallrealnumbers.
hoa [83]

Answer:

a)TRUE

b)FALSE

c)TRUE

d)FALSE

e)TRUE

f)TRUE

g)TRUE

h)FALSE

i)FALSE

j)TRUE

Step-by-step explanation:

a) For every x there is y such that  x^2=y:

 TRUE

This statement is true, because for every real number there is a square         number of that number, and that square number is also a real number. For example, if we take 6.5, there is a square of that number and it equals 39.0625.

b) For every x there is y such that  x=y^2:

 FALSE

For example, if x = -1, there is no such real number so that its square equals -1.

c) There is x for every y such that xy = 0

 TRUE

If we put x = 0, then for every y it will be xy=0*y=0

d)There are x and y such that x+y\neq y+x

 FALSE

There are no such numbers. If we rewrite the equation we obtain an incorrect statement:

                                   x+y \neq y+x\\x+y - y-y\neq 0\\0\neq 0

e)For every x, if   x \neq 0  there is y such that xy=1:

 TRUE

The statement is true. If we have a number x, then multiplying x with 1/x (Since x is not equal to 0 we can do this for ever real number) gives 1 as a result.

f)There is x for every y such that if y\neq 0 then xy=1.

TRUE

The statement is equivalent to the statement in e)

g)For every x there is y such that x+y = 1

TRUE

The statement says that for every real number x there is a real number y such that x+y = 1, i.e. y = 1-x

So, the statement says that for every real umber there is a real number that is equal to 1-that number

h) There are x and y such that

                                  x+2y = 2\\2x+4y = 5

We have to solve this system of equations.

From the first equation it yields x=2-2y and inserting that into the second equation we have:

                                   2(2-2y)+4y=5\\4-4y+4y=5\\4=5

Which is obviously false statement, so there are no such x and y that satisfy the equations.

FALSE

i)For every x there is y such that

                                     x+y=2\\2x-y=1

We have to solve this system of equations.

From the first equation it yields x=2-y  and inserting that into the second equation we obtain:

                                        2(2-y)-y=1\\4-2y-y=1\\4-3y=1\\-3y=1-4\\-3y=-3\\y=1

Inserting that back to the first equation we obtain

                                            x=2-1\\x=1

So, there is an unique solution to this equations:

x=1 and y=1

The statement is FALSE, because only for x=1 (and not for every x) exists y (y=1) such that

                                         x+y=2\\2x-y=1

j)For every x and y there is a z such that

                                      z=\frac{x+y}{2}

TRUE

The statament is true for all real numbers, we can always find such z. z is a number that is halway from x and from y.

5 0
3 years ago
.002 centimeters=_____ mm <br> Help?
Rina8888 [55]

Answer:

0.02

Step-by-step explanation:

divide it by 10.

4 0
2 years ago
Read 2 more answers
Lucy had $72 which is 9 times more than Xavier had
WINSTONCH [101]

Answer:

multiply 72 times 9

Step-by-step explanation: 648

6 0
3 years ago
Read 2 more answers
Can you please help me
ioda

Answer: 1/6

Step-by-step explanation:

<u>Given:</u>

4/9 and 11/18

<u>Solve:</u>

<em>STEP ONE: Make the denominators equal by determining the LCM</em>

LCM = Least Common Multiple

First Five multiples of 9 = 9, 18, 27, 36, 45

First FIve multiples of 18 = 18, 36, 54, 72, 90

As we can see from the list above, both 18 and 36 overlap, however, 18 is less than 36. Therefore, 18 is the LCM.

<em>STEP TWO: Compare the size and determine the greater one.</em>

4/9 = (4 × 2) / (9 × 2) = 8/18

11/18 = 11/18

Since 11 > 8, therefore, 11/18 is greater than 8/18

<em>STEP THREE: Find the difference between the two fractions.</em>

 11/18 - 4/9

=11/18 - 8/18

=(11 - 8) / 18

= 3 / 18

= 1/6

Hope this helps!! :)

Please let me know if you have any questions

6 0
3 years ago
1. How many planes are shown in the figure?
g100num [7]

Answer:8 planes are shown in the figure

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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