Question:
You are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on constructing a confidence interval; however, you are not sure how many citizens should be included in the sample. If you want your sample estimate to be within 5 years of the actual mean with a confidence level of 97% , how many citizens should be included in your sample? Assume that the standard deviation of the ages of all the citizens in this community is 18 years.
Answer:
61.03
Step-by-step explanation:
Given:
Standard deviation = 18
Sample estimate = 5
Confidence level = 97%
Required:
Find sample size, n.
First find the Z value. Using zscore table
Z-value at a confidence level of 97% = 2.17
To find the sample size, use the formula below:





Sample size = 61.03
Answer:

Step-by-step explanation:
<h3>Trigonometry:</h3>
75 = 45 + 30
Sin (x + y) = Sin x *Cos y + Cos x * Sin y
Sin (45 + 30) = Sin 45 * Cos 30 + Cos 45 * Sin 30
To simplify that expression, you need to combine line terms so in order for you to go that, you would need to combine -9n, +4n, and -10n
You would get: 16m-15n
Answer:
Hiii, I really did try my best, hopefully this helps :)
Step-by-step explanation:
1st: 37.5 units
2nd: 34.5 units
3rd: 24 + 9.125 π units
4th: 42 units
5th: 49.5 units
Answer:
Looks like identity property of multiplication
Step-by-step explanation: