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3 years ago

App182.studyisland.com/cfw/test/practice-session/a56do?CFID=14068

Physics

1 answer:

Alex3 years ago

8 0

The amount of matter contained by an object is called mass.

A. mass

<u>Explanation:</u>

Mass is fundamentally a property of any physical amount and it is additionally the estimation of the resistance from the acceleration when force is applied on an object. The mass equals the quality of the gravitational force on a body.

Mass, in material science, the quantitative proportion of idleness, a crucial property of all matter. The greater the mass of a body, the littler the change created by an applied power. The mass of an object can be portrayed by its capacity to oppose a given power (we once in a while call this a body's inertial mass and subsequently mass is personally connected with the idea of inertia).

This is a straightforward result of Newton's second law where the power F, on a body is equivalent to the mass m, times the speeding up an, it encounters, ie:

F=ma or m=F/a

Mass of an object can not be zero but weight can be zero. The mass and weight of an object are different things.

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Se lanza desde el suelo verticalmente hacia arriba un objeto con una velocidad inicial de 20 m/s. Calcula: a)Posición y velocida

djverab [1.8K]

Answer:

Ver las respuestas a continuacion.

Explanation:

Para solucionar este tipo de problemas debemos de utilizar la siguiente ecuacion de la cinematica.

$v_{f}=v_{o}-g*t$

Donde:

Vf = velocidad final [m/s]

Vo = velocidad inicial = 20 [m/s]

g = aceleración gravitacional = 9.81 [m/s²]

t = tiempo = 1 [s]

El signo negativo de la aceleración gravitacional significa que el objeto se mueve en dirección contraria a la aceleración gravitacional.

$v_{f}=20-9.81*(1)\\v_{f}=10.19[m/s]$

La altura máxima se logra cuando la velocidad final es cero, es decir no existe movimiento alguno para que siga subiendo el objeto. Debemos utilizar la siguiente ecuación de la cinemática.

$v_{f}^{2} =v_{o}^{2}-2*g*y$

Donde:

y = elevación [m]

$0 = 20^{2} -2*9.81*y\\19.62*y=400\\y=20.38 [m]$

Podemos calcular el tiempo máximo que toma el objeto en subir.

$v_{f}=v_{o}-g*t$

$0 = 20 -9.81*t\\9.81*t=20\\t=2.04[s]$

Ahora del numeral b) sabemos la distancia maxima, de esta manera y utilizando la siguiente ecuacion podemos calcular el tiempo de caida, Debemos tener en cuenta que ahora la velocidad final es igual a la velocidad inicial = 0.

$y=y_{o}+v_{o}*t+\frac{1}{2}*g*t^{2}$

$20.38 = 0*t + 0.5*9.81*t^{2} \\20.38 = 4.905*t^{2}\\t=\sqrt{\frac{20.38}{4.905} } \\t=2.04[s]$

Entonces el tiempo total es igual a:

t = 2.04 + 2.04

$t = 4.076 [s]$

4 0

3 years ago

Jack (mass 52.0 kg ) is sliding due east with speed 8.00 m/s on the surface of a frozen pond. he collides with jill (mass 49.0 k

dybincka [34]

We must write down laws of conservation of momenta and energy.
For the law of conservation of momenta will we will use two axes. One will be x-axis that will correspond to the east, and the other one will be y-axis corresponding to the north. Jack will be marked as 1 and Jill will be marked as 2.
Law of conservation of energy:
$\frac{m_1v_1^2}{2}=\frac{m_1v'_1^2}{2}+ \frac{m_2v_2^2}{2}\\
m_2v_2^2=m_1v_1^2-m_1v_1'^2\\
v_2=\sqrt{\frac{m_1v_1^2-m_1v_1'^2}{m_2}$
This will give us Jill's velocity after the colision.
$v_2=6.43\frac{m}{s}$
Law of conservation of momenta:
$x: m_1v_1=m_1v_1'cos(34)+m_2v_2cos(\theta)\\
y: 0=m_1v_1'sin(34)-m_2v_2sin(\theta)\\$
We will use the second equation to get the angle at which the Jill is traveling:
$0=m_1v_1'sin(34)-m_2v_2sin(\theta)\\
m_2v_2sin(\theta)=m_1v_1'sin(34)\\
sin(\theta)=\frac{m_1v_1'sin(34)}{m_2v_2}\\
\theta=sin^{-1}(\frac{m_1v_1'sin(34)}{m_2v_2})$
When we plug all the number we get:
$\theta=27.45^\circ$
Please note that this is the angle below the x-axis.

6 0

3 years ago

Two students, Nora and Allison, are both the same age when Allison hops aboard a flying saucer and blasts off to achieve a cruis

White raven [17]

Answer:

23.38 years

Explanation:

Speed of Allison = 0.83 c = v

Time passed according to Allison = Δt = 29.5 years

Time dilation

$\Delta t'=\frac{\Delta t}{\sqrt{1-\frac{v^2}{c^2}}}\\\Rightarrow \Delta t'=\frac{29.5}{\sqrt{1-\frac{0.83^2c^2}{c^2}}}\\\Rightarrow \Delta t'=\frac{29.5}{\sqrt{1-0.83^2}}\\\Rightarrow \Delta t'=52.88\ years$

For Nora 52.88 years would have passed

So, their age difference would be 52.88-29.5 = 23.38 years

6 0

4 years ago

If you are in a spaceship that is sitting on the surface of a planet, you feel your weight. How does this compare to the weight

nordsb [41]

Answer:

You will feel more weight if it is accelerating out of the planet.

You will feel less weight if it is accelerating towards the planet.

Explanation:

The weight that you are observing or feeling is basically due to the change in acceleration of your fall or rising up in the spaceship. When the acceleration is stationary on the surface, you experience your normal weight due to the gravitational acceleration of that planet.

When the spaceship accelerates above or out of the planet you experience acceleration more than the acceleration of gravity hence more weight.

When the spaceship accelerates towards the planet you experience acceleration less than the acceleration of gravity hence less weight.

If the spaceship is free falling at the gravitational acceleration you experience a zero weight

8 0

3 years ago

Q.1 Newton's second law gives the measure of--------------. 1)Acceleration 2) Force 3) Momentum 4)Angular momentum

posledela

Answer:

1. Acceleration

Explanation:

Newtons Second law gives the measure of acceleration

4 0

4 years ago