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PSYCHO15rus [73]
4 years ago
6

The distance between two stations is 1995 Km. How much time will it take to cover the distance at an average speed of 19KM/hour

Physics
1 answer:
Flura [38]4 years ago
5 0
105 hours or 4.375 days
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A fruit bat falls from the roof of a cave. We know that her potential energy was
bulgar [2K]

Answer:

v = 15.65 m/s

Explanation:

We use conservation of mechanical energy between initial (i) and final (f) states:

Pi + KEi = Pf + KEf

At the top of the cave at the instant the bat starts to fall, there is only potential energy since the bat's velocity is zero.

Pi = m g h = 600 J

and the KEi = 0 J (no velocity)

Knowing the height of the cave's roof (12.8 m) , we can find the mass of the bat:

m = 600 J / (g 12.5) = 4.9 kg

Using conservation of mechanical energy, the final state is:

Pf + KEf = 600 J

with Pf = 0 (just touching the ground)

KEf= 1/2  4.9 (v^2)

and we solve for the velocity:

600 J = 0 + 1/2  4.9 (v^2)

v^2 = 600 * 2 / 4.9 = 244.9

v = 15.65 m/s

5 0
3 years ago
An automobile travels on a straight road for 40 km at 30 km/h. It then continues in the same direction for another 40 km at 60 k
Butoxors [25]

Answer:

The average velocity is 40km/h.

Explanation:

The average velocity is \bar{v}=\frac{\Delta x }{\Delta t}, where \Delta x is the distance traveled and \Delta t the time elapsed.

The distance traveled is clearly 80km since it's all done in the same direction, we only need to know the time elapsed. For this we calculate the time elapsed on the first part, and add it to the time elapsed on the second part using always the formula \Delta t=\frac{\Delta x }{v}, where v is the velocity on each part, which is constant.

The time elapsed for the first part is \Delta t_1=\frac{40 km}{30km/h}=\frac{4}{3}h, and the time elapsed for the second part is \Delta t_2=\frac{40 km}{60km/h}=\frac{2}{3}h, giving us a total time of \Delta t_1+\Delta t_2=\frac{4}{3}h+\frac{2}{3}h=2h.

Finally, we can calculate the average velocity: \bar{v}=\frac{80km}{2h}=40km/h.

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3 years ago
The oscillation of the 2.0-kg mass on a spring is described by x = 3.0 cos (4.0 t) where x is in centimeters and t is in seconds
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X is the answer because x can be any thing
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3 years ago
If the force between two fixed Charged spheres is F and you triple the charge on one sphere and also triple the distance between
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Since the charge has a direct proportionality, the increase will be a factor of three. But, since you triple the distance, which has an inversely squared proportion, it will be 3/9 F or 1/3 F.

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F_s = \frac{Kq_1q_2}{r^2}

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