To develop this problem we will start from the definition of entropy as a function of total heat, temperature. This definition is mathematically described as

Here,
Q = Total Heat
T = Temperature
The total change of entropy from a cold object to a hot object is given by the relationship,

From this relationship we can realize that the change in entropy by the second law of thermodynamics will be positive. Therefore the temperature in the hot body will be higher than that of the cold body, this implies that this term will be smaller than the first, and in other words it would imply that the magnitude of the entropy 'of the hot body' will always be less than the entropy 'cold body'
Change in entropy  is smaller than
 is smaller than 
Therefore the correct answer is C. Will always have a smaller magnitude than the change in entropy of the cold object
 
        
             
        
        
        
Answer:
15.065ft
Explanation:
To solve this problem it is necessary to consider the aerodynamic concepts related to the Drag Force.
By definition the drag force is expressed as:

Where
 is the density of the flow
 is the density of the flow
V = Velocity
 = Drag coefficient
= Drag coefficient
A = Area
For a Car is defined the drag coefficient as 0.3, while the density of air in normal conditions is 1.21kg/m^3
For second Newton's Law the Force is also defined as,

Equating both equations we have:



Integrating


Here,






Replacing: 




 
        
             
        
        
        
Answer:
a)   D_ total = 18.54 m,   b)        v = 6.55 m / s
Explanation:
In this exercise we must find the displacement of the player.
a) Let's start with the initial displacement, d = 8 m at a 45º angle, use trigonometry to find the components
            sin 45 = y₁ / d
            cos 45 = x₁ / d
            y₁ = d sin 45
            x₁ = d sin 45
            y₁ = 8 sin 45 = 5,657 m
            x₁ = 8 cos 45 = 5,657 m
The second offset is d₂ = 12m at 90 of the 50 yard
             y₂ = 12 m
             x₂ = 0
total displacement
           y_total = y₁ + y₂
           y_total = 5,657 + 12
           y_total = 17,657 m
           x_total = x₁ + x₂
           x_total = 5,657 + 0
           x_total = 5,657 m
           D_total =   17.657 i^+ 5.657 j^  m
           D_total = Ra (17.657 2 + 5.657 2)
           D_ total = 18.54 m
b) the average speed is requested, which is the offset carried out in the time used
            v = Δx /Δt
the distance traveled using the pythagorean theorem is
          r = √ (d1² + d2²)
           r = √ (8² + 12²)
           r = 14.42 m
The time used for this shredding is
          t = t1 + t2
          t = 1 + 1.2
          t = 2.2 s
let's calculate the average speed
          v = 14.42 / 2.2
          v = 6.55 m / s