1 year ago

Calculate the speed at the edge of a disc of radius 8.5 cm that rotates at the rate of 2.5 rev/s.

Mathematics

1 answer:

Zina [86]1 year ago

6 0

Answer:

11 m/s

Step-by-step explanation:

cause 8.5 add 2.5 then 11 then m/s

You might be interested in

What is the degree of this polynomial below ?<br> 2x^5 + 4x^3 -3x^8

xeze [42]

Answer:

Step-by-step explanation:

the degree is the highest exponent value

8 0

3 years ago

Can someone help me please

butalik [34]

Answer:

A. Point T

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

WILL GIVE BRAINIEST ANSWER IF ANSWER IS CORRECT

IRISSAK [1]

F(x) = x+4
f(4) = 8, f(5) = 9
Change = 1

f(x) = 3x-7
f(-3) = -16, f(5) = 8
Change = 24/8 = 3

f(x) = 9x+1
f(-5) = -44, f(-2) = -17
Change = 27/3 = 9

f(x) = 2x+9
f(1) = 11, f(2) = 13
Change = 2

In order: f(x) = 9x+1, f(x) = 3x-7, f(x) = 2x+9, f(x) = x+4

4 0

3 years ago

Read 2 more answers

The volume of a rectangular box is (x3 - 7x2 - 9x + 63) cubic units. Determine the dimensions of the rectangular box by factorin

Shalnov [3]

Hello,
well done.
As x^3-7x²-9x+63=(x-3)(x+3)(x-7) we must have x>3 and x>-3 and x>7 thus x>7

Explanations:
x^3-7x²-9x+63=x^3-9x+(-7x²+63)=x(x²-9)-7(x²-9)=(x²-9)(x-7)=(x+3)(x-3)(x-7)

6 0

3 years ago

How do i prove 2sec^2x-2sec^2xsin^2-sin^2x-cos^2x=1

kramer

$2\sec^2x-2\sec^2x\sin^2x-\sin^2x-\cos^2x=2\sec^2x(1-\sin^2x)-(\sin^2x+\cos^2x)$

Since $\sin^2x+\cos^2x=1$ , you have

$2\sec^2x(1-\sin^2x)-(\sin^2x+\cos^2x)=2\sec^2x\cos^2x-1$

and since $\sec x=\dfrac1{\cos x}$ , you end up with $2-1=1$ .

6 0

3 years ago