Answer:
<h3>
41</h3>
Step-by-step explanation:
The consecutive integers are increasing by 1
x ← the smallest integer
x+1 ← the middle integer
x+1+1 = x+2 ← the largest integer
x + x+1 + x+2 = 120
3x + 3 = 120
÷3 ÷3
x + 1 = 40
-1 -1
x = 39
x+2 = 39 + 2 = 41
Answer:
y= -x/6-9
x= -6y-54
Step-by-step explanation:
I think the answer is 151.
Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
