Answer:
Molality = 0.0862 mole/kg
Explanation:
Molality = (number of moles of solute)/(mass of solvent in kg)
Number of moles of solute = (mass of Creatinine in the blood sample)/(Molar mass of Creatinine)
To obtain the mass of creatinine in 10 mL of blood. We're told that 1 mg of Creatinine is contained in 1 decilitre of blood.
1 decilitre = 100 mL
1 mg of Creatinine is contained in 100 mL of blood
x mg of Creatinine is contained in 10 mL of blood.
x = (1×10/100) = 0.1 mg = 0.0001 g
Molar mass of Creatinine (C₄H₇N₃O) = 113.12 g/mol
Number of moles of Creatinine in the 10 mL blood sample = (0.0001/113.12) = 0.000000884 moles
Mass of 10 mL of blood = density × volume = 1.025 × 10 = 10.25 mg = 0.01025 g = 0.00001025 kg
Molality of normal creatinine level in a 10.0-ml blood sample = (0.000000884/0.00001025)
Molality = 0.0862 moles of Creatinine per kg of blood.
Hope this Helps!!!
830 mL
The volume of an 2.3 m solution with 212 grams of calcium chloride (cacl2) dissolved is 830 mL.
The solution has a concentration of 2.3 mol/L.
<h3>a) Moles of CaCl2</h3>
Molar mass of CaCl2 = 110.98 g/mol
Moles of CaCl2 = 212 g CaCl2 x (1 mol CaCl2/110.98 g CaCl2)
= 1.910 mol CaCl2
<h3>b) Volume of solution</h3>
V = 1.910 mol CaCl2 x (1 L solution/2.3 mol CaCl2) = 0.83 L solution
= 830 mL solution
<h3>How much CaCl2 is there in the solution by molarity?</h3>
- The number of moles is 0.125 x 2 = 0.25 mol since the molarity is 2.0M.
- To get the answer of 27.745 g, simply multiply this by the molar mass of calcium chloride, which is 110.98 g/mol.
To learn more about CaCl2 solution visit:
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Answer:
CO2
cardon dioxide is produced
Answer:
Scientific Law
Explanation: Earth will ALWAYS attract objects to the center of itself because of gravity. This will never be disproven.
