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Harlamova29_29 [7]
2 years ago
6

How many kJ are required to completely vaporize a 25.0 gram sample of water at 100°C? general formula:

Chemistry
1 answer:
Reptile [31]2 years ago
5 0

Answer:

56500J

Explanation:

Given parameters:

Mass of water  = 25g  = 0.025kg

Temperature of the water  = 100°C

Unknown:

Amount of heat required to vaporize the water  = ?

Solution:

The amount of heat required to vaporize the water is a function of the mass of the water and the latent heat of vaporization of water.

         H = mL

H is the amount of heat

m is the mass

L is the latent heat of vaporization of water = 22.6 x 10⁵J/Kg

  H  = 0.025 x 22.6 x 10⁵ = 56500J

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This is an incomplete question, here is a complete question.

The balanced chemical reaction is:

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Explanation :

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