How many kJ are required to completely vaporize a 25.0 gram sample of water at 100°C? general formula:

Chemistry

1 answer:

Reptile [31]3 years ago

5 0

Answer:

56500J

Explanation:

Given parameters:

Mass of water = 25g = 0.025kg

Temperature of the water = 100°C

Unknown:

Amount of heat required to vaporize the water = ?

Solution:

The amount of heat required to vaporize the water is a function of the mass of the water and the latent heat of vaporization of water.

H = mL

H is the amount of heat

m is the mass

L is the latent heat of vaporization of water = 22.6 x 10⁵J/Kg

H = 0.025 x 22.6 x 10⁵ = 56500J

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Answer:

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Explanation:

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If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other), the direct rule of three must be applied. To solve a direct rule of three, the following formula must be followed:

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