The balanced chemical reaction will be:
C2H2 + 5/2O2 = 2CO2 + H2O
We are given the amount of C2H2 being burned. This will be our starting point.
64.0 g C2H2 (1 mol C2H2 / 26.02 g C2H2) (1 mol H2O/1mol C2H2) ( 18.02 g H2O/1mol H2O) = 44.32 g H2O.
Thus, the answer is 44.32 g H2O.
The number of mole of oxygen gas, O₂ in the cylinder given the data is 0.5 mole
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation:
Mole = mass / molar mass
<h3>How to determine the mole of O₂</h3>
From the question given, the following data were obtained:
- Mass of O₂ = 16 g g
- Molar mass of O₂ = 32 g/mol
- Mole of O₂ =?
Mole = mass / molar mass
Mole of O₂ = 16 / 32
Mole of O₂ = 0.5 mole
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Ammonium Nitrate has the formula NH4NO3, and has a formula weight of 80.043 grams/mole. We can convert the amount in the problem to moles using this conversion factor. Divide 435 by 80.043 to find the number of moles.
435/80.043 = 5.435
This amount of Ammonium Nitrate contains 5.44 moles of substance, adjusted for significant figures.
Answer:
3 moles of calcium oxide are formed
Explanation:
Based on the reaction of Calcium Ca, with oxygen, O₂, to produce calcium oxide, CaO is:
2Ca + O₂ → 2CaO
<em>where 2 moles of calcium produce 2 moles of Calcium oxide.</em>
That means, if 3 moles of Ca react in presence of oxygen:
3 moles of calcium oxide are formed
The balanced chemical reaction is:
<span>Ca + Cl2 = CaCl2
</span>
We are given the amount of calcium metal to be used for this reaction. This will be the starting point for the calculations.
56 g Ca ( 1 mol Ca / 40.08 g Ca) (1 mol Cl2 / 1 mol Ca) ( 22.414 L Cl2 / 1 mol Cl2 ) = 31.32 L Cl2 gas produced from the reaction
