Based on the information provided and the assumption that the mole ratio of the acid to the base is 1:1, the molarity of the acid would be 0.0425 M
<h3>Acid/base Titration</h3>
Using the equation:
CaVa = CbVb
This is based on the assumption that the stoichiometric mole ratio of the acid to the base is 1:1.
Ca = CbVb/Va
0.1 x 25.5/60 = 0.0425 M
More on acid/base titration can be found here: brainly.com/question/2728613
The molarity is 0.151 mol/L
Hope it helps.
Answer:
Number of moles of CoCl3 = 0.09 moles
Explanation:
Given data:
Mass of CoCl₃ = 12.1 g
Number of moles = ?
Solution:
First of all we will calculate the molar mass.
Molar mass of CoCl3 = 28.01 + (35.5×3)
Molar mass of CoCl3 = 28.01 + 106.5
Molar mass of CoCl3 = 134.51 g/mol
Number of moles of CoCl3 = mass / molar mass
Number of moles of CoCl3 = 12.1 g/134.51 g/mol
Number of moles of CoCl3 = 0.09 moles
Answer:
2.1 kg of water
Explanation:
Step 1: Given data
- Moles of lithium bromide (solute): 4.3 moles
- Molality of the solution (m): 2.05 m (2.05 mol/kg)
- Mass of water (solvent): ?
Step 2: Calculate the mass of water required
Molality is equal to the moles of solute divided by the kilograms of solvent.
m = moles of solute/kilograms of solvent
kilograms of solvent = moles of solute/m
kilograms of solvent = 4.3 mol /(2.05 mol/kg) = 2.1 kg
