Question

95-a(b+c) when a= 9, b = 3 and c=7.4 I don’t get how to solve this please put an explanation

Answer 1

Notice that in the statement of the exercise are the values of a, b and c. Then, to evaluate the given expression, we replace the given values of a, b, and c. So, we have:

$\begin{gathered} a=9 \\ b=3 \\ c=7.4 \\ 95-a\mleft(b+c\mright) \\ \text{ We replace the given values} \\ 95-a(b+c)=95-9(3+7.4) \\ 95-a(b+c)=95-9(10.4) \\ 95-a(b+c)=95-93.6 \\ 95-a(b+c)=\boldsymbol{1.4} \end{gathered}$

Therefore, the result of evaluating the given expression when a = 9, b = 3, and c = 7.4 is 1.4.