For this problem, the confidence interval is the one we are looking
for. Since the confidence level is not given, we assume that it is 95%.
The formula for the confidence interval is: mean ± t (α/2)(n-1) * s √1 + 1/n
Where:
<span>
</span>
α= 5%
α/2
= 2.5%
t
0.025, 19 = 2.093 (check t table)
n
= 20
df
= n – 1 = 20 – 1 = 19
So plugging in our values:
8.41 ± 2.093 * 0.77 √ 1 + 1/20
= 8.41 ± 2.093 * 0.77 (1.0247)
= 8.41 ± 2.093 * 0.789019
= 8.41 ± 1.65141676
<span>= 6.7586 < x < 10.0614</span>
The answer is p , merry Christmas
7x - 4y = -28
3x +4y = -12
Using the elimination method because y is already eliminated
10x = -40
So x = -4
Then plug the -4 into the first equation....
7(-4) - 4y = -28
-28 - 4y = -28
-4y = 0
y = 0
I got: -4,0
3.2 over 0.4 is equivalent to 8
Answer:
5195
Step-by-step explanation:
30% of 8450 is 2535
8450 - 2535 = 5195